我正在尝试使用 Snowflake 中的后一个函数解析 Snowflake 中的以下嵌套 JSON,但我希望“GoalTime”中的每个嵌套列都显示为一列。例如,
GoalTime_InDoorOpen
2020-03-26T12:58:00-04:00
GoalTime_InLastOff
null
GoalTime_OutStartBoarding
2020-03-27T14:00:00-04:00
"GoalTime": [
{
"GoalName": "GoalTime_InDoorOpen",
"GoalTime": "2020-03-26T12:58:00-04:00"
},
{
"GoalName": "GoalTime_InLastOff"
},
{
"GoalName": "GoalTime_InReadyToTow"
},
{
"GoalName": "GoalTime_OutTowAtGate"
},
{
"GoalName": "GoalTime_OutStartBoarding",
"GoalTime": "2020-03-27T14:00:00-04:00"
},
最佳答案
或者如果您有很多行(看起来是航类),因此您需要每个航类的列,此代码就是您想要的内容
with data as (
select flight_code, parse_json(json) as json from values ('nz101','{GoalTime:[{"GoalName": "GoalA", "GoalTime": "2020-03-26T12:58:00-04:00"}, {"GoalName": "GoalB"}]}'),
('nz201','{GoalTime:[{"GoalName": "GoalA"}, {"GoalName": "GoalB", "GoalTime": "2020-03-26T12:58:00-02:00"}]}')
j(flight_code, json)
), unrolled as (
select d.flight_code, f.value:GoalName as goal_name, f.value:GoalTime as goal_time
from data d,
lateral flatten (input => json:GoalTime) f
)
select *
from unrolled
pivot(min(goal_time) for goal_name in ('GoalA', 'GoalB'))
order by flight_code;
它给出了结果:
FLIGHT_CODE 'GoalA' 'GoalB'
nz101 "2020-03-26T12:58:00-04:00" null
nz201 null "2020-03-26T12:58:00-02:00"
关于sql - 在 Snowflake 中解析 JSON,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/61240518/