c# - 每行换行而不是每个字符换行？

Question

变量myReceivedLines(代码如下)中从串行端口接收的数据为每个字符显示新行，而不是为每个“句子”逐行显示。

有没有办法让“句子”出现在单独的行而不是字符上？

   //Fields
    string myReceivedLines;

    //subscriber method for the port.DataReceived Event
    private void DataReceivedHandler(object sender, System.IO.Ports.SerialDataReceivedEventArgs e)
    {
        SerialPort sp = (SerialPort)sender;
        myReceivedLines = sp.ReadExisting();
    }


    protected override void SolveInstance(IGH_DataAccess DA)
    {

        List<string> gcode = new List<string>();
        DA.GetDataList(0, gcode);
        string selectedportname = default(string);
        DA.GetData(1, ref selectedportname);
        int selectedbaudrate = default(int);
        DA.GetData(2, ref selectedbaudrate);
        bool connecttodevice = default(bool);
        DA.GetData(3, ref connecttodevice);

        SerialPort port = new SerialPort(selectedportname, selectedbaudrate, Parity.None, 8, StopBits.One); //Create the serial port
        port.DtrEnable = true;   //enables the Data Terminal Ready (DTR) signal during serial communication (Handshaking)

        port.Open();             //Open the port

        if ((port.IsOpen) && (connecttodevice == true))
        {
            port.DataReceived += new SerialDataReceivedEventHandler(DataReceivedHandler);
            DA.SetDataList(0, myReceivedLines);
        }

Answer 1

假设您输入包含换行符，请使用 ReadLine为了达成这个。请注意，如果您没有设置正确的 ReadTimeout，这将是一个阻塞调用。我会将 ReceivedBytesThreshold 设置为预期的平均行长度，并将我的行存储在适合我需要的任何集合中。

//Fields
List<string> myReceivedLines;

//subscriber method for the port.DataReceived Event
private void DataReceivedHandler(object sender, System.IO.Ports.SerialDataReceivedEventArgs e)
{
    SerialPort sp = (SerialPort)sender;
    while(sp.BytesToRead > 0)
    {
        try 
        {
            myReceivedLines.Add(sp.ReadLine());
        }
        catch(TimeOutException) 
        {
            break;
        }
    }
}