我是 SQL Server 新手。我有一个 SQL 查询,我执行了所有联合操作,两个单独的查询有分组依据。
select top 5
Starttime, convert(date,row_date) as Date,
sum(acdcalls + abncalls) [Offered],
sum(acdcalls) [Handled],
sum(abncalls) [Abandoned],
sum(acdcalls1 + acdcalls2 + acdcalls3 + acdcalls4 + acdcalls5) [Answered within SLA],
case
when sum(acdcalls) != 0
then cast((sum(acdcalls1 + acdcalls2 + acdcalls3 + acdcalls4 + acdcalls5)) * 1.0 / sum((acdcalls)) * 1.0 * 100 as decimal(10, 2))
else 0
end as [SLA in %]
from
db1
where
row_date = getdate()
group by
Starttime, row_Date
union all
select top 5
Starttime, convert(date,row_date) as Date,
sum(acdcalls + abncalls) [Offered],
sum(acdcalls) [Handled],
sum(abncalls) [Abandoned],
sum(acdcalls1 + acdcalls2 + acdcalls3 + acdcalls4 + acdcalls5) [Answered within SLA],
case
when sum(acdcalls) != 0
then cast((sum(acdcalls1 + acdcalls2 + acdcalls3 + acdcalls4 + acdcalls5)) * 1.0 / sum((acdcalls)) * 1.0 * 100 as decimal(10, 2))
else 0
end as [SLA in %]
from
db2
where
row_date = getdate()
group by
Starttime, row_Date
Starttime
列具有通用值。我想对结果进行分组 Starttime
。我怎样才能做到这一点?任何帮助将不胜感激
最佳答案
您需要先进行并集,然后再进行聚合。以下示例使用子查询,但如果您愿意,也可以使用临时表:
Select StartTime, Row_Date, sum(acdcalls+abncalls)...[other sums here]
From (
select * from db1
union all
select * from db2
) a
group by StartTime, RowDate
如果需要,您仍然可以在子查询中包含 where 子句和特定列(上面的示例仅在 db1 和 db2 具有相同顺序的相同列时才有效 - 否则您将需要指定您的列)。不过,如果您将两个选择限制为 Row_Date = GetDate(),我不确定为什么要按 Row_Date 分组。
关于sql - 对所有结果进行分组 SQL Server,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29993173/