我偶然发现了这个问题Python - intersection between a list and keys of a dictionary ，不幸的是没有所需的声誉来询问:
为什么会这样？
d1 = {'200:200':{'foo':'bar'},'300:300':{'foo':'bar'}}
l1 = ['200:200', '90:728']
keys = d1.keys() & l1
最佳答案
d1.keys() 的结果是一个类似 View 的集合。
Keys views are set-like since their entries are unique and hashable. If all values are hashable, so that (key, value) pairs are unique and hashable, then the items view is also set-like. (Values views are not treated as set-like since the entries are generally not unique.) For set-like views, all of the operations defined for the abstract base class collections.abc.Set are available (for example, ==, <, or ^).
来自https://docs.python.org/3/library/stdtypes.html#dictionary-view-objects
& 的第二个参数只需要是可哈希对象的可迭代对象(尽管文档中没有说明)。
参见https://docs.python.org/3/library/stdtypes.html#set.intersection
关于python - 为什么我可以使用按位 AND 检查列表是否包含字典的键？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/32144787/