我想使用名为 Failed.py
这是我目前所拥有的:
myFile = open('today','r')
ips = {}
for line in myFile:
parts = line.split(' ')
if parts[1] == 'Failure':
if parts[0] in ips:
ips[pars[0]] += 1
else:
ips[parts[0]] = 0
for ip in [k for k, v in ips.iteritems() if v >=5]:
#write to file called Failed.py
最佳答案
file = open('Failed.py', 'w')
file.write('whatever')
file.close()
这里有一个更pythonic的版本,它会自动关闭文件,即使被包装的 block 中有异常:
with open('Failed.py', 'w') as file:
file.write('whatever')
关于Python 保存到文件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9536714/