我正在尝试创建一个脚本来对当前事件工作表/选项卡上的表格进行排序,但我收到无法识别的错误。我不断收到 The coordinates of the range are outside the dimensions of the sheet.
。我的表中有从 columnA 到 columnQ 的数据。 columnA 中的数据是标识号,columnB 到 columnQ 包含公式。我的脚本做错了什么?
var sortFirst = 7; //index of column to be sorted by; 1 = column A, 2 = column B, etc.
var sortFirstAsc = true; //Set to false to sort descending
var sortSecond = 8;
var sortSecondAsc = true;
var sortThird = 9;
var sortThirdAsc = true;
var activeSheet = SpreadsheetApp.getActiveSheet();
var sheetName = activeSheet.getSheetName(); //name of sheet to be sorted
var sheet = SpreadsheetApp.getActive().getSheetByName(sheetName);
var range = sheet.getRange(2, 1, sheet.getLastRow(), sheet.getLastColumn());
range.sort([{column: sortFirst, ascending: sortFirstAsc}, {column: sortSecond, ascending: sortSecondAsc}, {column: sortThird, ascending: sortThirdAsc}]);
最佳答案
很有可能是线路上的错误
var range = sheet.getRange(2, 1, sheet.getLastRow(), sheet.getLastColumn());
很有可能的解决办法是改成
var range = sheet.getRange(2, 1, sheet.getLastRow() - 1, sheet.getLastColumn());
上面是因为范围从第 2 行开始并且因为工作表很可能在最后一行有内容。
相关
关于google-apps-script - "The coordinates of the range are outside the dimensions of the sheet"排序时出错,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49157222/