是否有内置的 Numpy/Scipy 函数来查找四分位数范围?我自己可以很容易地做到这一点,但是存在 mean()
基本上是 sum/len
...
def IQR(dist):
return np.percentile(dist, 75) - np.percentile(dist, 25)
最佳答案
np.percentile
接受多个百分位参数,你最好这样做:
q75, q25 = np.percentile(x, [75 ,25])
iqr = q75 - q25
或
iqr = np.subtract(*np.percentile(x, [75, 25]))
比对 percentile
进行两次调用:
In [8]: x = np.random.rand(1e6)
In [9]: %timeit q75, q25 = np.percentile(x, [75 ,25]); iqr = q75 - q25
10 loops, best of 3: 24.2 ms per loop
In [10]: %timeit iqr = np.subtract(*np.percentile(x, [75, 25]))
10 loops, best of 3: 24.2 ms per loop
In [11]: %timeit iqr = np.percentile(x, 75) - np.percentile(x, 25)
10 loops, best of 3: 33.7 ms per loop
关于python - 你如何在 Numpy 中找到 IQR?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/23228244/