函数 fetchData 返回一个 promise ,然后我通过链接 promise
在generateURL函数中处理该 promise 。与 .then
但是它返回 Promise
const fetch = require('node-fetch');
const fetchData = async () => {
return await fetch('https://jsonplaceholder.typicode.com/todos/1');
};
const generateURL = () => {
const baseURL = 'https://cdn.test.com/';
fetchData().then((res) => {
const data = res.json();
console.log('data', data);
const id = data.id;
console.log('id', id);
const generatedURL = `${baseURL}${id}`;
return generatedURL;
});
};
最佳答案
减少了一点代码,而不是添加多个 promise 解析
const fetch = require('node-fetch');
const everything = async () =>{
const response = await fetch('https://jsonplaceholder.typicode.com/todos/1');
const {id} = await response.json();
return `https://cdn.test.com/${id}`
}
everything().then((res)=>console.log(res));
关于javascript - Promise.then() 返回 Promise { <pending> },我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/65755094/