python-3.x - 两个正则表达式的串联

Question

我有以下导出的文本文件:

14:00:01 type1 "xyz" has no relationships... ಠ_ಠ
14:00:01 type2 "xyza" has no relationships... ಠ_ಠ
14:00:01 type2 "aaaa" has no relationships... ಠ_ಠ
14:00:01 type3 "asdg" has no relationships... ಠ_ಠ
14:00:01 type4 "dhj" has no relationships... ಠ_ಠ

我正在尝试找到一种方法来从此文件中检索两个信息

1. 类型(在本例中为时间之后、双引号内之前的元素)
2. 双引号内的内容

预期输出:

type1 xyz

type2 xyza

type2 aaaa

type3 asdg

type4 dhj

使用我当前的代码，我可以获取双引号内的内容，但我不知道如何获取类型并将其与我的正则表达式合并:

import os, yaml
import argparse
import re
with open('stackoverflow.txt') as f:
    content = f.readlines()
    matches=re.findall(r'\"(.+?)\"',str(content))#get the content within the double quote
for x in matches:
    print(x)

当前输出:

xyz

xyza

aaaa

asdg

dhj

Answer 1

如果您的 txt 文件始终具有该结构，我会简单地这样做:

with open('stackoverflow.txt') as f:
    matches = [' '.join(line.split(' ')[1:3]) for line in f.readlines()]

for x in matches:
    print(x)

输出:

type1 "xyz"
type2 "xyza"
type2 "aaaa"
type3 "asdg"
type4 "dhj"