python - 如何从选定列表中选择一个项目？

Question

玩家输入字母 (a-z)。 该程序从以输入字母开头的列表中随机生成一个单词，并显示绘制的单词。 如何使输入的键成为列表的名称，可以从中随机选择以输入字符开头的单词？ 可能还有什么其他方法可以做到这一点？ 谢谢。

代码: 随机导入

import pygame
# list of letters (a-z)
a = ["ananas", "arbuz", "agrest"]
b = ["banan", "balon", "beton"]
c = ["cytryna", "cebula", "candy"]
# ...
z = ["zebra", "zombie", "zonk"]

pygame.init()
screen = pygame.display.set_mode((0, 0))
running = True
while running:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            running = False

        if event.type == pygame.KEYDOWN :
            if event.key == pygame.K_ESCAPE:
                running = False
            else:
                print(event.unicode)

pygame.quit()

Answer 1

我使用字典实现了以下功能，尽管这不是必需的。根据您想要对单词列表执行的操作，您可以使用或不使用字典来编写脚本。 (两者都应该很容易直接实现到您的 pygame 脚本中)

import keyboard
import random

a = ["ananas", "arbuz", "agrest"]
b = ["banan", "balon", "beton"]
c = ["cytryna", "cebula", "candy"]
# ...

words_dict = {}
words_dict['a'] = a
words_dict['b'] = b
words_dict['c'] = c
# ...

while True: 
    try:  
        if keyboard.is_pressed('a'):
            print(random.choice(words_dict['a']))
            break 
        elif keyboard.is_pressed('b'):
            print(random.choice(words_dict['b']))
            break 
        elif keyboard.is_pressed('c'):
            print(random.choice(words_dict['c']))
            break 
        # implement more elif here
    except:
        break 

您也可以直接创建一个包含所有内容的字典，而不是像我上面那样为每个列表分配一个键到字典中:

words_dict = {
    'a': ["ananas", "arbuz", "agrest"],
    'b': ["banan", "balon", "beton"],
    # and so on
}

不使用字典:

import keyboard
import random

a = ["ananas", "arbuz", "agrest"]
b = ["banan", "balon", "beton"]
c = ["cytryna", "cebula", "candy"]
# ...

while True: 
    try:  
        if keyboard.is_pressed('a'):
            print(random.choice(a))
            break 
        elif keyboard.is_pressed('b'):
            print(random.choice(b))
            break 
        elif keyboard.is_pressed('c'):
            print(random.choice(c))
            break 
        # implement more elif here
    except:
        break 

================================================== =============

更新:以下脚本检测用户的按键点击并检索/显示正确的信息，而无需使用案例来检查用户输入的按键。

import random
import msvcrt

words_dict = {
    'a': ["ananas", "arbuz", "agrest"],
    'b': ["banan", "balon", "beton"],
    'c': ["cytryna", "cebula", "candy"]
    # ... 
}

while True:
    if msvcrt.kbhit():
        key_pressed = msvcrt.getch()

        try:
            if words_dict.__contains__(key_pressed.decode('utf-8')):
                print(random.choice(words_dict[key_pressed.decode('utf-8')]))
                break
            else:
                print(f'Input "{key_pressed.decode("utf-8")}" is not recognized. Please try again!')
        except:
            break

请注意，变量 key_pressed 的类型为 bytes，在使用之前需要像上面一样进行解码。