我有两个列表如下:
list1 <- list(c(`0` = 0L, `25` = 0L, `100` = 1L, `250` = 1L, `500` = 1L,
`1000` = 1L, Infinity = 3L), c(`0` = 0L, `25` = 0L, `100` = 1L,
`250` = 1L, `500` = 1L, Infinity = 4L))
list2 <- list(c(`0` = 0L, `25` = 0L, `100` = 0L, `250` = 2L, `500` = 1L,
`1000` = 1L, Infinity = 3L), c(`0` = 0L, `25` = 0L, `100` = 1L,
`250` = 1L, `500` = 1L, Infinity = 4L))
我想将 list2[[1]]
append 到 list1[[1]]
并 append list2[[2]]
到list1[[2]]
。这样:
list_out <- list(c(`0` = 0L, `25` = 0L, `100` = 1L, `250` = 1L, `500` = 1L,
`1000` = 1L, Infinity = 3L, `0` = 0L, `25` = 0L, `100` = 0L, `250` = 2L, `500` = 1L,
`1000` = 1L, Infinity = 3L), c(`0` = 0L, `25` = 0L, `100` = 1L,
`250` = 1L, `500` = 1L, Infinity = 4L, `0` = 0L, `25` = 0L, `100` = 1L,
`250` = 1L, `500` = 1L, Infinity = 4L))
谁能帮我解释一下我该怎么做?
最佳答案
您可以使用lapply
和c()
。
lapply(1:length(list1), function(x) c(list1[[x]], list2[[x]]))
或者maply
与append
或c
:
mapply(append, list1, list2)
输出
[[1]]
0 25 100 250 500 1000 Infinity 0
0 0 1 1 1 1 3 0
25 100 250 500 1000 Infinity
0 0 2 1 1 3
[[2]]
0 25 100 250 500 Infinity 0 25
0 0 1 1 1 4 0 0
100 250 500 Infinity
1 1 1 4
检查它是否与您的list_out
相同:
identical(lapply(1:length(list1), function(x) c(list1[[x]], list2[[x]])), list_out)
[1] TRUE
identical(mapply(append, list1, list2), list_out)
[1] TRUE
关于r - 追加两个列表列表的列表,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/72159588/