我目前正在使用一个如下所示的数据框:
Example <- structure(list(ID = c(12301L, 12301L, 15271L, 11888L, 15271L,
15271L, 15271L), StationOwner = c("Brian", "Brian", "Simon",
"Brian", "Simon", "Simon", "Simon"), StationName = c("Red", "Red",
"Red", "Green", "Yellow", "Yellow", "Yellow"), Parameter = c("Rain - Daily",
"Temperature -Daily", "VPD - Daily", "Rain - Daily", "Rain - Daily",
"Temperature -Daily", "VPD - Daily")), class = "data.frame", row.names = c(NA,
-7L))
我正在考虑使用 str_detect 来过滤所有以“Rain –”开头的观察结果，并在名为“Rain”的新列下添加后面的内容。我已经能够使用 str_detect 过滤掉以“Rain”开头的值，但还没有找到自动分配它们的方法。有没有特定的功能可以帮助解决这个问题？恳请指点，谢谢!
我想要实现的期望输出示例:
Desired <- structure(list(ID = c(12301L, 15271L, 12301L, 15271L
), StationOwner = c("Brian", "Simon", "Brian", "Simon"), StationName = c("Red",
"Red", "Green", "Yellow"), Rain = c("Daily", NA, "Daily", "Daily"
), Temperature = c("Daily", NA, NA, "Daily"), VDP = c(NA, "Daily",
NA, "Daily")), class = "data.frame", row.names = c(NA, -4L))
最佳答案
直接使用pivot_wider:
pivot_wider(Example, names_from = Parameter, values_from = Parameter,
names_repair = ~str_remove(.,' .*'),values_fn = ~str_remove(.,'.*- ?'))
# A tibble: 4 x 6
ID StationOwner StationName Rain Temperature VPD
<int> <chr> <chr> <chr> <chr> <chr>
1 12301 Brian Red Daily Daily NA
2 15271 Simon Red NA NA Daily
3 11888 Brian Green Daily NA NA
4 15271 Simon Yellow Daily Daily Daily
关于r - 基于str_detect对列进行分类，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/72724479/