Python - 克隆列表

Question

我想克隆 list1 中的每个元组，以便元组 [1, 0, 1] 中的列表被克隆为与原始元组恰好有一个不同的数字，这样它添加到新列表以使其:

[([0, 0, 1], 'a'), ([0, 1, 1], 'a'), ([1, 0, 0], 'a')]

但是，它返回给我的是

[[[0, 1, 0], 'a'], [[0, 1, 0], 'a'], [[0, 1, 0], 'a']]. 

list1 = [([1, 0, 1], 'a')]
list2 = list1.copy()
newlist = []
for x in list2:
    for i in range(len(x[0])):
        new_x = list(x).copy()
        if x[0][i] == 1:
            new_x[0][i] -= 1
            newlist.append(new_x)
        elif x[0][i] == 0:
            new_x[0][i] += 1
            newlist.append(new_x)
print(newlist)

Answer 1

您需要将它们转换回元组

list1 = [([1, 0, 1], 'a')]
list2 = list1.copy()
newlist = []
for x in list2:
    for i in range(len(x[0])):
        new_x = list(x).copy() # <- converting to the list
        if x[0][i] == 1:
            new_x[0][i] -= 1
            newlist.append(tuple(new_x)) # <- converting to the tuple
        elif x[0][i] == 0:
            new_x[0][i] += 1
            newlist.append(tuple(new_x)) # <- converting to the tuple
print(newlist)