我想知道 FactoryGirl 中是否有与 find_or_initialize_by
等效的方法来解决以下问题:
目标是该模型使用具有相同国家/地区的两个表。我不想为国家使用序列(正如我为电子邮件找到的那样)。
Country 有一个唯一性约束,但我的主要问题是当我调用一次 FactoryGirl.create(:click) 时,它会创建两次相同的 Country 记录
因此,验证在测试中失败。
R规范:
# models/click_spec.rb
describe Click do
it "should have a valid constructor" do
FactoryGirl.create(:click).should be_valid
end
end
工厂:
# factories/countries.rb
FactoryGirl.define do
factory :country do
name "United States"
slug "us"
end
end
# factories/offers.rb
FactoryGirl.define do
factory :offer do
association :country, factory: :country
# Other columns
end
end
# factories/users.rb
FactoryGirl.define do
factory :user do
association :country, factory: :country
# Other columns
end
end
# factories/clicks.rb
FactoryGirl.define do
factory :click do
association :offer, factory: :offer
association :user, factory: :user
# Other columns
end
end
型号:
class Country < ActiveRecord::Base
validates :name, :slug,
presence: true,
uniqueness: { case_sensitive: false }
validates :slug,
length: { is: 2 }
end
最佳答案
你应该能够通过使用 initialize_with
来完成这项工作:
FactoryGirl.define do
factory :country do
name "United States"
slug "us"
initialize_with { Country.find_or_create_by_name(name) }
end
end
这将始终使用同一个国家。您可能希望嵌套工厂以允许其他工厂使用不同的名称:
FactoryGirl.define do
factory :country do
initialize_with { Country.find_or_create_by_name(name) }
factory :united_states do
name "United States"
slug "us"
end
end
end
关于ruby-on-rails - FactoryGirl 中的 find_or_initialize_by,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/22874292/