努力编写可以在 XML 中生成嵌套元素的查询。谁能帮忙
输入:
SELECT EmpName AS [Name],
EmpDOB AS [Birthdate],
EmpSalary AS [WageAmount],
Add1 AS [Address1],
Add2 AS [Address2],
Mobile AS [Mobile]
FROM Employee
FOR XML PATH
输出:(这有附加信息作为嵌套元素)
<Employee>
<Name>Conrad</Name>
<Birthdate>14-oct-76</BirthDate>
<WageAmount>10000</WageAmount>
<AdditionalInfo>
<Address1>Washington DC</Address1>
<Address2>DC</Address2>
<Mobile>989898989</Mobile>
</AdditionalInfo>
</Employee>
最佳答案
在这种情况下,最简单的方法是使用正斜杠分隔符在列别名中指定路径:
SELECT EmpName AS [Name],
EmpDOB AS [Birthdate],
EmpSalary AS [WageAmount],
Add1 AS [AdditionalInfo/Address1],
Add2 AS [AdditionalInfo/Address2],
Mobile AS [AdditionalInfo/Mobile]
FROM Employee
FOR XML PATH ('Employee')
您还可以使用在选择列中返回 XML 的子查询来实现。像这样:
SELECT EmpName AS [Name],
EmpDOB AS [Birthdate],
EmpSalary AS [WageAmount],
(select
Add1 AS [AdditionalInfo/Address1],
Add2 AS [AdditionalInfo/Address2],
Mobile AS [AdditionalInfo/Mobile]
from Employee EmpAddInfo
where EmpAddInfo.EmployeeID=Employee.EmployeeID
FOR XML PATH('AdditionalInfo'), TYPE
)
FROM Employee
FOR XML PATH ('Employee')
在你的情况下这样做很愚蠢,因为字段都在同一个表中,但如果你有一个要加入的详细表,你会这样做。
关于SQL 服务器 : Nesting Elements with FOR XML PATH,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37734539/