typescript - 获取传递给 typescript 的泛型参数的类名

Question

如何获取传递的泛型参数的类名

class Sample<T>{ 
    public getTypeName(): void { 
        alert(T.name)
        //or
        alert(new T().constructor.name)
    }
}
class Person { 
    public FullName:string
}
new Sample<Person>().getTypeName()

我需要将输出打印为“Person”？

Answer 1

虽然类型泛型类型在编译时被清除，但您可以传入类的构造函数并获取其名称:

class Sample<T>{ 
    public constructor(public tCtor: new (...args:any[]) => T){}
    public getTypeName(): void { 
        console.log(this.tCtor.name)
    }
}
class Person { 
    public FullName!:string
}
new Sample(Person).getTypeName()