Python:如何使用同一个 try/except block 简化多个语句

Question

我有这样一个代码块:

try:
    gitlab.gl_delete_project(gitlab_project_id)
except DevOpsError as e:
    if e.status_code != 404:
            raise e
try:
    redmine.rm_delete_project(redmine_project_id)
except DevOpsError as e:
    if e.status_code != 404:
        raise e
try:
    if harbor_project_id is not None:
        harbor.hb_delete_project(harbor_project_id)
except DevOpsError as e:
    if e.status_code != 404:
        raise e

每个方法都可能引发 DevOpsError，在某些情况下，我只想忽略异常，或者在其他时间重新引发它。

既然 try/except block 都是相同的，有没有办法简化代码？

编辑:有人向我提出了类似的问题，但它没有告诉我如何将参数传递给方法。

Answer 1

定义函数并根据需要多次调用它:

def try_to_delete(delete_method, object):
    try:
        delete_method(object)
    except DevOpsError as e:
        if e.status_code != 404:
            raise e

try_to_delete(gitlab.gl_delete_project, gitlab_project_id)
try_to_delete(redmine.rm_delete_project, redmine_project_id)
if harbor_project_id is not None:  
    try_to_delete(harbor.hb_delete_project, harbor_project_id)