我们有一个列表列表:
[['130', '2020-12-17 12:02:19', [52.1846976, 21.0525275]], ['213', '2020-12-17 12:02:22', [52.1757618, 21.2319711]]
并希望将其转换为这样的数据框:
index 2020-12-17 12:02:19 2020-12-17 12:02:22
130 [52.1846976, 21.0525275] NaN
213 NaN [52.1757618, 21.2319711]
想不通。
最佳答案
你可以将你的列表变成一个字典列表，然后将索引显式地提供给构造器:
In [1]: import pandas as pd
In [2]: data = [['130', '2020-12-17 12:02:19', [52.1846976, 21.0525275]], ['213', '2020-12-17 12:02:22', [52.1757618, 21.2319711]]]
In [3]: pd.DataFrame([{col: val} for _, col, val in data], index=[item[0] for item in data])
Out[3]:
2020-12-17 12:02:19 2020-12-17 12:02:22
130 [52.1846976, 21.0525275] NaN
213 NaN [52.1757618, 21.2319711]
关于python - 如何将列表列表转换为第一个元素是索引，第二个是列名的数据框，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/65340535/