我有一个字符串变量，我想在其中删除某些单词，但许多其他单词可能是部分匹配，我不想删除。我想删除单词，当且仅当它们完全匹配时。
clear
* Add in some example data
input index str50 words
1 "more mor morph test"
2 "ten tennis tenner tenth keeper"
3 "badder baddy bad other"
end
* I create a copy to compare obefore/after strip
gen strip_words = words
* This is a list of words I want removed. In reality, this is a fairly long list
local removs "mor ten bad"
* For each of words, remove the complete word from teh string
foreach w of local removs {
replace strip_words = subinstr(strip_words, "`w'","", .)
}
list
+---------------------------------------------------------------+
| index words strip_words |
|---------------------------------------------------------------|
1. | 1 more mor morph test e ph test |
2. | 2 ten tennis tenner tenth keeper nis ner th keeper |
3. | 3 badder baddy bad other der dy other |
+---------------------------------------------------------------+
我已经尝试用 replace strip_words = ""+ strip_words + "" 填充一些空格，但这也会删除分隔其他单词的空格。我想要的输出是
+-------------------------------------------------------------------------+
| index words strip_words |
|-------------------------------------------------------------------------|
1. | 1 more mor morph test more morph test |
2. | 2 ten tennis tenner tenth keeper tennis tenner tenth keeper |
3. | 3 badder baddy bad other badder baddy other |
+-------------------------------------------------------------------------+
'''
最佳答案
请参阅帮助字符串函数了解subinword()。
clear
* Add in some example data
input index str50 words
1 "more mor morph test"
2 "ten tennis tenner tenth keeper"
3 "badder baddy bad other"
end
* I create a copy to compare obefore/after strip
gen strip_words = words
* This is a list of words I want removed. In reality, this is a fairly long list
local removs "mor ten bad"
* For each of words, remove the complete word from teh string
foreach w of local removs {
replace strip_words = subinword(strip_words, "`w'","", .)
}
replace strip_words = itrim(strip_words)
关于Stata 从字符串中删除整个单词，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/65598883/