javascript - 如果 else 没有按预期工作，我的逻辑有问题吗？

Question

我正在尝试遍历一个数组，如果有任何匹配的元素，它应该将 true 推送到一个新数组，否则返回 false。

const wordPerformance = []
const wordsReviewed   = "candy, cattle, cat, call, cheat";
const wordsIncorrect  = "candy, cattle, call, cheat";

wordsReviewed.split(/,\s?/).forEach((word) => {
  if (wordsIncorrect.includes(word)) {
    wordPerformance.push(false);
  } else {
    console.log(word) //unreachable, though 'cat' should be logged
    wordPerformance.push(true);
  }
});

console.log(wordPerformance);

按照这个逻辑，wordPerformance 应该返回

[false, false, true, false, false]

然而，它正在返回

[false, false, false, false, false]

也许有什么我没有看到？

Answer 1

您必须首先拆分 wordsIncorrect 字符串，就像您对 wordsReviewed 所做的那样，这样它就可以与项目进行比较，而不包括包含某些内容的字符串结束就像匹配“猫”和“牛”

这是固定的例子

const wordPerformance = []
const wordsReviewed = "candy, cattle, cat, call, cheat";
const wordsIncorrect = "candy, cattle, call, cheat";
const wordsIncorrectSplitted = wordsIncorrect.split(/,\s?/);

wordsReviewed.split(/,\s?/).forEach((word) => {
  if (wordsIncorrectSplitted.includes(word)) {
    wordPerformance.push(false);
    } else {
    console.log(word) //unreachable, though 'cat' should be logged
    wordPerformance.push(true);
  }
});

console.log(wordPerformance);