我现在很笨……
print_r($terms);
这是……
Array
(
[7] => stdClass Object
(
[term_id] => 7
[name] => Testwhatever
[slug] => testwhatever
[term_group] => 0
[term_taxonomy_id] => 7
[taxonomy] => event_type
[description] =>
[parent] => 0
[count] => 2
[object_id] => 8
)
)
如何打印
slug?
我认为 print print($terms->slug)
应该可以完成这项工作,但它说:“尝试获取非对象的属性”
更新:
function get_event_term($post) {
$terms = get_the_terms( (int) $post->ID, 'event_type' );
if ( !empty( $terms ) ) {
print_r($terms);
return $terms[7]->slug;
}
}
最佳答案
它是一个对象数组(即使它只包含索引“7”处的单个条目),而不是单个对象
echo $terms[7]->slug;
有多个“事物”
foreach ($terms as $term) echo $term->slug;
关于PHP & WordPress : print array content,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/11538029/