kdb 凡人/众神!!
我有一个日期时间字符串数组，但格式不同
> leads[`firstConversion]
"Wed May 20 2020 08:56:54 GMT-0700 (PDT)"
"Wed May 20 2020 08:56:56 GMT-0700 (PDT)"
"Wed May 20 2020 08:56:56 GMT-0700 (PDT)"
"Wed May 20 2020 08:56:56 GMT-0700 (PDT)"
"Wed May 20 2020 08:56:57 GMT-0700 (PDT)"
"Wed May 20 2020 08:56:58 GMT-0700 (PDT)"
"Wed May 20 2020 08:56:58 GMT-0700 (PDT)"
"Wed May 20 2020 08:56:59 GMT-0700 (PDT)"
"Wed May 20 2020 08:57:00 GMT-0700 (PDT)"
"Wed May 20 2020 08:57:01 GMT-0700 (PDT)"
"Wed May 20 2020 09:06:32 GMT-0700 (PDT)"
"Wed May 20 2020 09:06:32 GMT-0700 (PDT)"
"Wed May 20 2020 09:06:33 GMT-0700 (PDT)"
"Wed May 20 2020 09:06:33 GMT-0700 (PDT)"
"Wed May 20 2020 09:06:35 GMT-0700 (PDT)"
"Wed May 20 2020 09:06:35 GMT-0700 (PDT)"
"Wed May 20 2020 09:07:07 GMT-0700 (PDT)"
"Wed May 20 2020 09:07:09 GMT-0700 (PDT)"
"Wed May 20 2020 09:07:09 GMT-0700 (PDT)"
"Wed May 20 2020 09:07:10 GMT-0700 (PDT)"
将它们转换为原生 kdb 时间戳 2020.05.20D09:07:10.0000 的最佳方法是什么？
最佳答案
取决于每个字符串相关部分的索引的可预测性/一致性......如下所示
q)x!"P"$4_'x
"Wed May 20 2020 08:56:54 GMT-0700 (PDT)"| 2020.05.20D08:56:54.000000000
"Wed May 20 2020 08:56:56 GMT-0700 (PDT)"| 2020.05.20D08:56:56.000000000
"Wed May 20 2020 08:56:56 GMT-0700 (PDT)"| 2020.05.20D08:56:56.000000000
"Wed May 20 2020 08:56:56 GMT-0700 (PDT)"| 2020.05.20D08:56:56.000000000
"Wed May 20 2020 08:56:57 GMT-0700 (PDT)"| 2020.05.20D08:56:57.000000000
q)
q)// or
q)
q)i:4+til -4+count first x
q)x!"P"$x[;i]
"Wed May 20 2020 08:56:54 GMT-0700 (PDT)"| 2020.05.20D08:56:54.000000000
"Wed May 20 2020 08:56:56 GMT-0700 (PDT)"| 2020.05.20D08:56:56.000000000
"Wed May 20 2020 08:56:56 GMT-0700 (PDT)"| 2020.05.20D08:56:56.000000000
"Wed May 20 2020 08:56:56 GMT-0700 (PDT)"| 2020.05.20D08:56:56.000000000
"Wed May 20 2020 08:56:57 GMT-0700 (PDT)"| 2020.05.20D08:56:57.000000000
q)
q)x:2000000#x
q)
q)\ts "P"$4_'x
495 161554832
q)\ts "P"$x[;i]
538 161554768
关于KDB 字符串到 kdb `timestamp`，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/64434253/