api - Gmail.Users.Messages.remove(me, id) - 未找到错误

Question

有没有其他人发现Advanced Gmail Service调用

`Gmail.Users.Messages.remove(me, id)`

现在出现错误？有人有办法解决吗？

我有一个可靠的脚本，每隔几个小时就会删除垃圾邮件和垃圾邮件。从 2017 年 2 月 21 日左右开始，即使传递了有效的线程 ID，它也会给出错误“未找到”。

这是脚本。我添加了一些日志消息

function deleteForever() {
  var threads = GmailApp.getSpamThreads(0, 100);
  var me = Session.getActiveUser().getEmail();
  for (var i = threads.length -1; i >=0; i--) {
     var thisid=threads[i].getId();
        Logger.log("Removing thread " +i + ' of ' + threads.length + " from Spam with ID = " + thisid);

    try {
    var thisthread=GmailApp.getThreadById(thisid);
    Logger.log("Found the thread.");
    Gmail.Users.Messages.remove(me, thisid);
    }catch(err) {
     Logger.log("Error " + err.message);
    };

  }
  Logger.log("Finished removing " + threads.length + " threads from Spam.");

  var threads = GmailApp.getTrashThreads(0, 100);
  for (var i = threads.length -1; i >=0; i--) {
        Logger.log("Removing thread " +i + ' of ' + threads.length + " from Trash");
    try {
    Gmail.Users.Messages.remove(me, threads[i].getId());
    } catch(err) {
    Logger.log("Error " + err.message);
    };
  }
  Logger.log("Finished removing " + threads.length + " threads from Trash.");
}

现在它只是给出一个未找到的错误。

[17-02-25 11:45:49:790 GMT] Removing thread 17 of 18 from Spam with ID = 15a6fe6c1a86a020
[17-02-25 11:45:49:829 GMT] Found the thread.
[17-02-25 11:45:49:959 GMT] Error Not Found
[17-02-25 11:45:49:959 GMT] Removing thread 16 of 18 from Spam with ID = 15a6fe6c168f4a03
[17-02-25 11:45:50:000 GMT] Found the thread.
[17-02-25 11:45:50:129 GMT] Error Not Found
[17-02-25 11:45:50:130 GMT] Removing thread 15 of 18 from Spam with ID = 15a6fed29f6650b3
[17-02-25 11:45:50:165 GMT] Found the thread.
[17-02-25 11:45:50:294 GMT] Error Not Found
.....
    `

请注意，在尝试删除操作之前，thisid 已明确设置为有效 ID。

Answer 1

您正在删除消息，而搜索功能正在获取线程。

使用

Gmail.Users.Threads.remove("me", threadId)

代替

Gmail.Users.Messages.remove("me", threadId);