我有一个将值写入特定实体的表单,我试图通过 Controller 中的函数编辑信息,非常简单。
银行 Controller .php
<?php
namespace App\Controller;
use App\Entity\Banco;
use App\Form\BancoType;
use App\Repository\BancoRepository;
use Doctrine\ORM\EntityManagerInterface;
use Symfony\Component\Form\FormFactoryInterface;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\HttpFoundation\RedirectResponse;
use Symfony\Component\HttpFoundation\Session\Flash\FlashBagInterface;
use Symfony\Component\HttpFoundation\Session\SessionInterface;
use Symfony\Component\Routing\Annotation\Route;
use Symfony\Component\Routing\RouterInterface;
use Symfony\Component\Security\Core\Authorization\AuthorizationCheckerInterface;
use Symfony\Component\HttpKernel\Exception\UnauthorizedHttpException;
use Sensio\Bundle\FrameworkExtraBundle\Configuration\Security;
use Symfony\Component\Security\Core\Authentication\Token\Storage\TokenStorageInterface;
class BancoController{
private $twig;
private $bancoRepository;
private $formFactory;
private $entityManager;
private $router;
private $flashBag;
private $authorizationChecker;
public function __construct(
\Twig_Environment $twig,
BancoRepository $bancoRepository,
FormFactoryInterface $formFactory,
EntityManagerInterface $entityManager,
RouterInterface $router,
FlashBagInterface $flashBag,
AuthorizationCheckerInterface $authorizationChecker
){
$this->twig = $twig;
$this->bancoRepository = $bancoRepository;
$this->formFactory = $formFactory;
$this->entityManager = $entityManager;
$this->router = $router;
$this->flashBag = $flashBag;
$this->authorizationChecker = $authorizationChecker;
}
/**
* @Route("/cadastro/bancos", name="cadastro_banco")
*/
public function index(TokenStorageInterface $tokenStorage){
$usuario = $tokenStorage->getToken()->getUser();
$html = $this->twig->render('bancos/index.html.twig', [
'bancos' => $this->bancoRepository->findBy(array('usuario' => $usuario))
]);
return new Response($html);
}
/**
* @Route("/banco/{id}", name="editar")
*/
public function editarBanco(Banco $banco, Request $request) {
$form = $this->formFactory->create(
BancoType::class,
$banco
);
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()){
$this->entityManager->flush();
return new RedirectResponse($this->router->generate('cadastro_banco'));
}
return new Response(
$this->twig->render(
'bancos/cadastro.html.twig',
['form' => $form->createView()]
));
}
/**
* @Route("/cadastro/cadastrar-banco", name="cadastro_banco-nova")
*/
public function cadastrar(Request $request, TokenStorageInterface $tokenStorage){
$usuario = $tokenStorage->getToken()->getUser();
$banco = new Banco();
$banco->setUsuario($usuario);
$form = $this->formFactory->create(BancoType::class, $banco);
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()){
$this->entityManager->persist($banco);
$this->entityManager->flush();
return new RedirectResponse($this->router->generate('cadastro_banco'));
}
return new Response(
$this->twig->render(
'bancos/cadastro.html.twig',
['form' => $form->createView()]
)
);
}
}
问题是,当我访问/banco/{id} 时,出现错误:
"Cannot autowire argument $banco of "App\Controller\BancoController::editarBanco()": it references class "App\Entity\Banco" but no such service exists."
我的 service.yaml 都是默认的,所以我想它应该会自动运行。 实体未显示在 bin/console debug:container 中。
如果我像这样在 services.yaml 中手动声明实体
App\Entity\Banco:
autowire: true
autoconfigure: true
public: false
它可以工作,但现在当我访问/banco/{id} 时,表单变成空的,没有数据库中存在的信息,如果我输入一些内容并提交,数据库中没有任何变化。
如果我转到调试工具栏并检查查询,它似乎是在查询登录用户的 ID,而不是实体“Banco”的 ID。
顺便说一句,这个实体表有一个 FK user_id。也许这就是问题所在? 我迷路了,所以我需要一点帮助。我是 PHP/Symfony 的新手。 谢谢
最佳答案
嗯,由于某些未知原因 sensio/framework-extra-bundle
没有完全安装。
我刚刚运行了 composer require annotations
,现在一切正常。
该死,浪费了 2 天的时间试图解决这个问题..
谢谢大家!
关于php - Symfony 4 - Autowiring 不工作,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51269736/