我的所有父子都在一个数组数据中。我想要的是在每个对象上添加一个新属性(级别)。
假设我有数据
var data = [
{
id: 1,
parent_id: 0,
name: "Child1",
},
{
id: 4,
parent_id: 1,
name: "Child11",
},
{
id: 5,
parent_id: 4,
name: "Child111",
},
{
id: 11,
parent_id: 4,
name: "Child112"
},
{
id: 13,
parent_id: 11,
name: "Child1121",
},
{
id: 21,
parent_id: 11,
name: "Child1122"
},
{
id: 22,
parent_id: 11,
name: "Child1123"
},
{
id: 24,
parent_id: 1,
name: 'Child12'
}
]
我想要一个基于 child 的 parent_id 的child-parent 关系，并在数组的每个对象中分配一个新属性作为表示深度级别的级别 child 基于其 parent 。我的预期结果是:
var data = [
{
id: 1,
parent_id: 0, <-------represents root
name: "Child1",
level:0 <--------level based on its parent_id
},
{
id: 4,
parent_id: 1
name: "Child11",
level:1
},
{
id: 5,
parent_id: 4,
name: "Child111",
level:2
},
{
id: 11,
parent_id: 4,
name: "Child112",
level:2
},
{
id: 13,
parent_id: 11,
name: "Child1121",
level:3
},
{
id: 21,
parent_id: 11,
name: "Child1122",
level:3
},
{
id: 22,
parent_id: 11,
name: "Child1123",
level:3
},
{
id: 24,
parent_id: 1,
name: 'Child12',
level:1
}
]
我的代码
function buildTree(elements, parent_id, level = 0) {
elements.forEach(element => {
if (element['parent_id'] == parent_id) {
console.log('parent_id', parent_id);
// elements.filter(item=>item!==element);
element['level'] = level;
}
else{
buildTree(elements,parent_id,level+1);
}
})
return elements;
}
最佳答案
对于已排序的数据，您可以为级别计数取一个对象并映射一个新的数据集。
var data = [{ id: 1, parent_id: 0, name: "Child1" }, { id: 4, parent_id: 1, name: "Child11" }, { id: 5, parent_id: 4, name: "Child111" }, { id: 11, parent_id: 4, name: "Child112" }, { id: 13, parent_id: 11, name: "Child1121" }, { id: 21, parent_id: 11, name: "Child1122" }, { id: 22, parent_id: 11, name: "Child1123" }, { id: 24, parent_id: 1, name: 'Child12' }],
levels = {},
result = data.map(o => ({
...o,
level: levels[o.id] = o.parent_id in levels
? levels[o.parent_id] + 1
: 0
}));
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }关于javascript - 在深度级别的基础上链接 child 和 parent ，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/61382030/