例如:
// Update: This GestureDetector is embedded inside a third party package
// that will invoke a series of animation along with the onTap button
GestureDetector(
onTap: () => print('Hey There!'),
child: Widget1(),
)
// Then another place in the same screen
GestureDetector(
onDoubleTap: () {
//Call the onTap of Widget1's GestureDetector
print('I'm Here');
}
child: Widget2(),
)
我想要的是当用户双击 Widget2
时,它还会调用 Widget1
的 onTap
回调。
更新:
所以我不想只调用传递到 Widget1
的 GestureDetector
的 onTap
的函数,而是以编程方式点击 onTap Widget1 的
GestureDetector
我该怎么做?
最佳答案
你可以这样做 -
创建您的手势检测器 -
GestureDetector gestureDetector = GestureDetector(
onTap: () {
setState(() {
_lights = !_lights;
});
},
child: Container(
color: Colors.yellow.shade600,
padding: const EdgeInsets.all(8),
child: const Text('TURN LIGHTS ON'),
),
);
创建一个按钮(或您想要使用的任何小部件)以在 GestureDetector gestureDetector.onTap()
上调用 onTap
,就像在另一个小部件上调用方法一样。 (我在这里使用的是 FlatButton
)-
FlatButton(
color: Colors.blue,
textColor: Colors.white,
disabledColor: Colors.grey,
disabledTextColor: Colors.black,
padding: EdgeInsets.all(8.0),
onPressed: () {
//Trigger the GestureDetector onTap event.
gestureDetector.onTap();
},
child: Text("Click Here"),
),
现在您可以点击 FlatButton 来调用 GestureDetector 上的 onTap
事件。
这是完整的例子-
import 'package:flutter/material.dart';
void main() => runApp(MyApp());
class MyApp extends StatelessWidget {
@override
Widget build(BuildContext context) {
return MaterialApp(
title: 'Flutter Demo',
debugShowCheckedModeBanner: false,
theme: ThemeData(
primarySwatch: Colors.blue,
),
home: MyHomePage(title: 'Gesture Detector On Tap'),
);
}
}
class MyHomePage extends StatefulWidget {
MyHomePage({Key key, this.title}) : super(key: key);
final String title;
@override
_MyHomePageState createState() => _MyHomePageState();
}
class _MyHomePageState extends State<MyHomePage> {
bool _lights = false;
@override
Widget build(BuildContext context) {
GestureDetector gestureDetector = GestureDetector(
onTap: () {
setState(() {
_lights = !_lights;
});
},
child: Container(
color: Colors.yellow.shade600,
padding: const EdgeInsets.all(8),
child: const Text('TURN LIGHTS ON'),
),
);
return Scaffold(
appBar: AppBar(
title: Text(widget.title),
),
body: Center(
child: Container(
alignment: FractionalOffset.center,
color: Colors.white,
child: Column(
mainAxisAlignment: MainAxisAlignment.center,
children: <Widget>[
Padding(
padding: const EdgeInsets.all(8.0),
child: Icon(
Icons.lightbulb_outline,
color: _lights ? Colors.yellow.shade600 : Colors.black,
size: 60,
),
),
gestureDetector,
SizedBox(height: 50.0),
FlatButton(
color: Colors.blue,
textColor: Colors.white,
disabledColor: Colors.grey,
disabledTextColor: Colors.black,
padding: EdgeInsets.all(8.0),
onPressed: () {
gestureDetector.onTap();
},
child: Text("Click Here"),
),
],
),
),
),
);
}
}
你会得到这样的东西-
关于flutter - 如何以编程方式模拟 Flutter 中按钮上的 onTap?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/63589071/