这是一系列cat语句
words = c("Hello","bar","ROCKnROLL","R","Supercalifragilisticexpialidocious")
for (i in 1:length(words))
{
cat(paste0(words[i], "\t: ",nchar(words[i]),"\n"))
}
Hello : 5
bar : 3
ROCKnROLL : 9
R : 1
Supercalifragilisticexpialidocious : 34
我该怎么做才能像这样对齐它们
Hello : 5
bar : 3
ROCKnROLL : 9
R : 1
Supercalifragilisticexpialidocious : 34
或者像这样
Hello : 5
bar : 3
ROCKnROLL : 9
R : 1
Supercalifragilisticexpialidocious : 34
或者最终像这样
Hello : 5
bar : 3
ROCKnROLL : 9
R : 1
Supercalifragilisticexpialidocious : 34
最佳答案
试试这个:
words = c("Hello","bar","ROCKnROLL","R","Supercalifragilisticexpialidocious")
for (i in 1:length(words)) {
print(sprintf("%-40s:%d", words[i], nchar(words[i])))
}
输出:
[1] "Hello :5"
[1] "bar :3"
[1] "ROCKnROLL :9"
[1] "R :1"
[1] "Supercalifragilisticexpialidocious :34"
关于r - 在 R 中对齐打印字符串的标准工具是什么？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/39536112/