python - 避免在嵌套循环python中重复

Question

所以我有嵌套循环和数组 [[0, 1], [0, 1, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4]]:

for x in string_list:
        for y in string_list:
            print(x,y)

为我提供输出

[0, 1] [0, 1]
[0, 1] [0, 1, 2, 3, 4, 5, 6]
[0, 1] [0, 1, 2, 3, 4]
[0, 1, 2, 3, 4, 5, 6] [0, 1]
[0, 1, 2, 3, 4, 5, 6] [0, 1, 2, 3, 4, 5, 6]
[0, 1, 2, 3, 4, 5, 6] [0, 1, 2, 3, 4]
[0, 1, 2, 3, 4] [0, 1]
[0, 1, 2, 3, 4] [0, 1, 2, 3, 4, 5, 6]
[0, 1, 2, 3, 4] [0, 1, 2, 3, 4]

但我有很多重复对，我做到了:

for x in range(0, len(string_list)):
      for y in range(x+1, len(string_list)): 
          print(x,y, string_list)

但它仅适用于 2 位数字对。 所以我想要的是:

[0, 1] [0, 1]
[0, 1] [0, 1, 2, 3, 4, 5, 6] 
[0, 1] [0, 1, 2, 3, 4]
**[0, 1, 2, 3, 4, 5, 6] [0, 1]** // avoid to output that pair cause we had that one 
[0, 1, 2, 3, 4, 5, 6] [0, 1, 2, 3, 4, 5, 6]
[0, 1, 2, 3, 4, 5, 6] [0, 1, 2, 3, 4]
[0, 1, 2, 3, 4] [0, 1]
**[0, 1, 2, 3, 4] [0, 1, 2, 3, 4, 5, 6]** // avoid to output that pair cause we had that one 
[0, 1, 2, 3, 4] [0, 1, 2, 3, 4]

不使用 itertools 可以吗？ 谢谢!

Answer 1

for k, x in enumerate(string_list):
    for y in string_list[k:]:
        print(x,y)