我有这个扁平化对象
{
"abc.def.ghi": "foo",
"abc.def.jkl": "bar"
}
我想写一个dataweave把它转换成原来的对象,即
{
"abc": {
"def": {
"ghi": "foo",
"jkl": "bar"
}
}
}
我试图避免对键进行硬编码,因为它是一个相当大的对象,所以我不想要这样的东西:
%dw 2.0
var test = {
"abc.def.ghi": "foo",
"abc.def.jkl": "bar"
}
output application/json
---
{
abc: {
def: {
ghi: test."abc.def.ghi",
jkl: test."abc.def.jkl"
}
}
}
我可以使用一些可用的 dataweave 函数组合来实现这一目标吗?
到目前为止,这是我尝试过的:
%dw 2.0
var test = {
"abc.def.ghi": "foo",
"abc.def.jkl": "bar"
}
output application/json
---
test mapObject ((value, key) ->
(key as String splitBy ".")[-1 to 0]
reduce ((item, acc = value) ->
(item): acc
/*
First item=ghi,acc=foo => acc = {ghi: "foo"}
next item=def, acc={ghi: "foo"} => acc={def:{ghi:"foo"}}
*/
)
)
但这会生成某种独立的嵌套 JSON 对。以下是上述代码的输出:
{
"abc": {
"def": {
"ghi": "foo"
}
},
"abc": {
"def": {
"jkl": "bar"
}
}
}
最佳答案
您可以尝试以下 dataweave 表达式,该表达式基于 Mohammad Mazhar Ansari 撰写的这篇 Apisero 文章:https://apisero.com/property-to-yaml-file-conversion-using-mulesoft/
%dw 2.0
var test = {
"abc.def.ghi": "foo",
"abc.def.jkl": "bar"
}
import * from dw::core::Strings
output application/json
fun generateArray (obj) = obj pluck (v, k) -> (k): v
fun isSubChildExists (key) = (((key) splitBy ("."))[1] != null)
fun propToJSON(key, value) = if (isSubChildExists(key)) {
(substringBefore(key, ".")) : propToJSON(substringAfter(key, "."), value)
}
else
(key): value
fun arrToObj(arr) = arr reduce ((env, obj={}) -> obj ++ env)
fun CombineObjBasedOnKey (Obj) =
if (typeOf(Obj) == Array and sizeOf(Obj..) > 1)
((Obj groupBy (item, index) -> keysOf(item)[0]) mapObject ((value, key, index) ->
(if (typeOf(value) == Array)
(key): CombineObjBasedOnKey(value..'$key')
else if (typeOf(value) == String)
value
else
(key): value
) as Object))
else
Obj[0]
---
CombineObjBasedOnKey(generateArray(test) map ((item, index) -> item mapObject ((value, key, index) -> propToJSON((key), value))
))
输出:
{
"abc": {
"def": {
"ghi": "foo",
"jkl": "bar"
}
}
}
关于json - 使用 Dataweave 2.0 将 JSON 对象展开为嵌套的 JSON 对象,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/63789863/