我有一个要排序的字典列表。这是我目前所拥有的:
output_list = [{'interface': '0/20', 'mac': '01:23:45:67:89:AB'},
{'interface': '0/16', 'mac': '12:34:56:78:9A:BC'},
{'interface': '0/31', 'mac': '23:45:67:89:AB:CD'},
{'interface': '0/5', 'mac': '34:56:78:9A:BC:DE'},
{'interface': '0/3', 'mac': '45:67:89:AB:CD:EF'}]
mac_list = sorted(output_list, key=lambda d: d['interface'])
pprint(mac_list)
但是，它并没有按照我想要的方式对字典进行排序。
"C:\Program Files\Python310\python.exe" "C:/Scripts/Python/test1.py"
[{'interface': '0/16', 'mac': '12:34:56:78:9A:BC'},
{'interface': '0/20', 'mac': '01:23:45:67:89:AB'},
{'interface': '0/3', 'mac': '45:67:89:AB:CD:EF'},
{'interface': '0/31', 'mac': '23:45:67:89:AB:CD'},
{'interface': '0/5', 'mac': '34:56:78:9A:BC:DE'}]
Process finished with exit code 0
我怎样才能让它看起来像这样:
[{'interface': '0/3', 'mac': '45:67:89:AB:CD:EF'},
{'interface': '0/5', 'mac': '34:56:78:9A:BC:DE'},
{'interface': '0/16', 'mac': '12:34:56:78:9A:BC'},
{'interface': '0/20', 'mac': '01:23:45:67:89:AB'},
{'interface': '0/31', 'mac': '23:45:67:89:AB:CD'}]
最佳答案
您需要从字符串中获取数字:
sorted(output_list, key=lambda d: int(d['interface'].split("/")[1]))
这假设界面的第一部分不会改变。
如果它发生变化，您需要用前导零重新格式化这两个部分:
sorted(output_list, key=lambda d: "/".join([f"{int(x):02d}" for x in d['interface'].split("/")]))
关于Python 按数字对字典列表进行排序，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/72715375/