javascript - Google Places API - radarSearch 按名称搜索

Question

我正在使用 Google Places API并使用 radarSearch 列出机构。但是，当我使用名称参数进行搜索时遇到问题。

它返回了几个地方，但我想得到确切的名字。

在此example ，我想返回“best buy”，但它返回的是与我正在搜索的词无关的地方。

            var map;
  var infoWindow;
  var service;

  function initialize() {
    map = new google.maps.Map(document.getElementById('map'), {
      mapTypeId: google.maps.MapTypeId.ROADMAP,
      center: new google.maps.LatLng(33.7490, -84.3880),
      zoom: 11,
      styles: [
        {
          stylers: [
            { visibility: 'simplified' }
          ]
        },
        {
          elementType: 'labels',
          stylers: [
            { visibility: 'on' }
          ]
        }
      ]
    });

    infoWindow = new google.maps.InfoWindow();
    service = new google.maps.places.PlacesService(map);

    performSearch();
  }

  function performSearch() {
    var request = {
      location: new google.maps.LatLng(33.7490, -84.3880),
      radius: 50000,
      name: "Best Buy"
    };
    service.radarSearch(request, callback);
  }

  function callback(results, status) {
    if (status != google.maps.places.PlacesServiceStatus.OK) {
      alert(status);
      return;
    }
    for (var i = 0, result; result = results[i]; i++) {
      createMarker(result);
    }
  }

  function createMarker(place) {
    var marker = new google.maps.Marker({
      map: map,
      position: place.geometry.location,
      icon: 'http://www.google.com/intl/en_us/mapfiles/ms/micons/yellow-dot.png'
    });

    google.maps.event.addListener(marker, 'click', function() {
      service.getDetails(place, function(result, status) {
        if (status != google.maps.places.PlacesServiceStatus.OK) {
          alert(status);
          return;
        }
        infoWindow.setContent(result.name);
        infoWindow.open(map, marker);
      });
    });
  }

  initialize();

Answer 1

根据 Google Places Search API ( https://developers.google.com/places/web-service/search )，在 name 参数上:

name — One or more terms to be matched against the names of places, separated by a space character. Results will be restricted to those containing the passed name values. Note that a place may have additional names associated with it, beyond its listed name. The API will try to match the passed name value against all of these names. As a result, places may be returned in the results whose listed names do not match the search term, but whose associated names do.

我认为你应该在它之前使用 \ 来转义你的空格字符:

var request = {
  location: new google.maps.LatLng(33.7490, -84.3880),
  radius: 50000,
  name: "Best\ Buy"
};

注意:在你的 fiddle 中，我只有“Best Buy...”/“Best Buy”/“.. Best Buy...”结果，我没有得到你的问题

使用此更改更新 fiddle(以及小的 jsfiddle 改进):https://jsfiddle.net/fautepdf/16/