python - 如何使用 View 在 Django 中保存内联表单集用户字段

标签 python django django-views overriding inline-formset

我一直在使用这个很棒的帖子 http://kevindias.com/writing/django-class-based-views-multiple-inline-formsets/设置我的网站。我想知道如何将用户字段自动保存到 View 中的内联表单集(我使用 blockquote 来更改原始内容)。中的 RecipeForm(另请参阅下文了解上下文)

self.object = form.save(commit=False)
self.object.owner = self.request.user
self.object.save()

很好地自动保存但不是

ingredient_form.owner= self.request.user

我知道 Django 建议使用 BaseInlineFormSet ,但出于许多不同的原因,大多数人建议将用户字段保存在 views.py 而不是表单或模型中。我将不胜感激任何建议或答案。这是完整的代码:

模型.py

from django.db import models


class Recipe(models.Model):
    owner = models.ForeignKey(User)
    title = models.CharField(max_length=255)
    description = models.TextField()


class Ingredient(models.Model):
    owner = models.ForeignKey(User)
    recipe = models.ForeignKey(Recipe)
    description = models.CharField(max_length=255)


class Instruction(models.Model):
    recipe = models.ForeignKey(Recipe)
    number = models.PositiveSmallIntegerField()
    description = models.TextField()

表单.py

from django.forms import ModelForm
from django.forms.models import inlineformset_factory 
from .models import Recipe, Ingredient, Instruction


class RecipeForm(ModelForm):
    class Meta:
        model = Recipe
    IngredientFormSet = inlineformset_factory(Recipe, Ingredient)
    InstructionFormSet = inlineformset_factory(Recipe, Instruction)

View .py

from django.http import HttpResponseRedirect
from django.views.generic import CreateView  
from .forms import IngredientFormSet, InstructionFormSet, RecipeForm
from .models import Recipe


class RecipeCreateView(CreateView):
    template_name = 'recipe_add.html'
    model = Recipe
    form_class = RecipeForm
    success_url = 'success/'

    def get(self, request, *args, **kwargs):
        """
        Handles GET requests and instantiates blank versions of the form
        and its inline formsets.
        """
        self.object = None
        form_class = self.get_form_class()
        form = self.get_form(form_class)
        ingredient_form = IngredientFormSet()
        instruction_form = InstructionFormSet()
        return self.render_to_response(
            self.get_context_data(form=form,
                                  ingredient_form=ingredient_form,
                                  instruction_form=instruction_form))

    def post(self, request, *args, **kwargs):
        """
        Handles POST requests, instantiating a form instance and its inline
        formsets with the passed POST variables and then checking them for
        validity.
        """
        self.object = None
        form_class = self.get_form_class()
        form = self.get_form(form_class)
        ingredient_form = IngredientFormSet(self.request.POST)
        instruction_form = InstructionFormSet(self.request.POST)
        if (form.is_valid() and ingredient_form.is_valid() and
            instruction_form.is_valid()):
            return self.form_valid(form, ingredient_form, instruction_form)
        else:
            return self.form_invalid(form, ingredient_form, instruction_form)

    def form_valid(self, form, ingredient_form, instruction_form):
        """
        Called if all forms are valid. Creates a Recipe instance along with
        associated Ingredients and Instructions and then redirects to a
        success page.
        """
        self.object = form.save(commit=False)
        self.object.owner = self.request.user
        self.object.save()
        ingredient_form.instance = self.object
        ingredient_form.owner= self.request.user
        ingredient_form.save()
        instruction_form.instance = self.object
        instruction_form.save()
        return HttpResponseRedirect(self.get_success_url())

    def form_invalid(self, form, ingredient_form, instruction_form):
        """
        Called if a form is invalid. Re-renders the context data with the
        data-filled forms and errors.
        """
        return self.render_to_response(
            self.get_context_data(form=form,
                                  ingredient_form=ingredient_form,
                                  instruction_form=instruction_form))

最佳答案

我做了更多研究,按照如何添加 custom formset saving 的指南,解决方案看起来有些复杂但针对 BaseInlineFormset 进行了修改正如刚才提到的。我意识到为每个模型创建 ModelForms 然后将它们链接到一个 View 中会更简单,因为在添加新配方 View 时我一次只需要一个子表单并且可以重用 ModelForm 代码。

这是运行良好的新代码!如果您需要更多信息,请随时联系。

表单.py

from django.forms import ModelForm
from .models import Recipe, Ingredient, Instruction


class RecipeForm(ModelForm):

    class Meta:
        model = Recipe
        exclude = ['owner',]

class IngredientForm(ModelForm):

    class Meta:
        model = Ingredient
        exclude = ['owner','recipe',]

class InstructionForm(ModelForm):

    class Meta:
        model = Instruction
        exclude = ['recipe',]

View .py

from .forms import IngredientForm, InstructionForm, RecipeForm


def add_new_value(request):
    rform = RecipeForm(request.POST or None)
    iform = IngredientForm(request.POST or None)
    cform = InstructionForm(request.POST or None)
    if rform.is_valid() and iform.is_valid() and cform.is_valid():
        rinstance = rform.save(commit=False)
        iinstance = iform.save(commit=False)
        cinstance = cform.save(commit=False)
        user = request.user
        rinstance.owner = user
        rinstance.save()
        iinstance.owner = user
        cinstance.owner = user
        iinstance.recipe_id = rinstance.id
        cinstance.recipe_id = rinstance.id
        iinstance.save()
        cinstance.save()
        return HttpResponseRedirect('/admin/')
    context = {
        'rform' : rform,
        'iform' : iform,
        'cform' : cform,
    }
    return render(request, "add_new_recipe.html", context)

模板:add_new_recipe.html

<!DOCTYPE html>
<html>
<head>
    <title>Add Recipe</title>
</head>

<body>
    <div>
        <h1>Add Recipe</h1>
        <form action="" method="post">
            {% csrf_token %}
            <div>
                {{ rform.as_p }}
                {{ iform.as_p }}
                {{ cform.as_p }}
            </div>
            <input type="submit" value="Add recipe" class="submit" />
        </form>
    </div>
</body>
</html>

关于python - 如何使用 View 在 Django 中保存内联表单集用户字段,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40478199/

相关文章:

django - 传递复选框值以在 django 中查看

python - Django Python - Itertools 没有使产品与拍卖销售额保持一致

python - 如何检测 pandas 上的特征重复

javascript - 在 Java 和 Python 中实现相同的 XorShift

将具有多个值的字典列表写入多个文件的Python脚本

python - 在 h2o AutoML 上检索 h2o AutoML 的交叉验证性能 (AUC) for holdout dataset

sql - 如何使用 Django ORM 创建交叉表 SQL 查询?

python - 如何在请求中流式传输文件?

python - 使用 django 作为 CLI 工具

python - 从与外键相关的模型中获取数据