from urllib.request import urlopen
from bs4 import BeautifulSoup
html= urlopen("http://www.pythonscraping.com/pages/page3.html")
soup= BeautifulSoup(html.read())
print(soup.find("img",{"src":"../img/gifts/img1.jpg"
}).parent.previous_sibling.get_text())
上面的代码工作正常但下面的代码不行。它给出了一个如上所述的属性错误。谁能告诉我原因?
from urllib.request import urlopen
from bs4 import BeautifulSoup
html= urlopen("http://www.pythonscraping.com/pages/page3.html")
soup= BeautifulSoup(html.read())
price =soup.find("img",{"src=":"../img/gifts/img1.jpg"
}).parent.previous_sibling.get_text()
print(price)
谢谢! :)
最佳答案
如果比较第一个和第二个版本,您会注意到:
首先: soup.find("img",{"src":"../img/gifts/img1.jpg"}).parent.previous_sibling.get_text()
- 注意:
“src”
第二个 soup.find("img","src=":"../img/gifts/img1.jpg"}).parent.previous_sibling.get_text()
- 注意:
"src="
第二个代码返回 Attribute Error:'NoneType' object has no attribute 'parent'
because it couldn't find src=="../img/gifts/img1.jpg "
在提供的汤中。
因此,如果您在第二个版本中删除 =
,它应该可以工作。
顺便说一句,你应该明确你想使用哪个解析器,否则 bs4
将返回以下警告:
UserWarning: No parser was explicitly specified, so I'm using the best available HTML parser for this system ("lxml"). This usually isn't a problem, but if you run this code on another system, or in a different virtual environment, it may use a different parser and behave differently.
To get rid of this warning, change code that looks like this:
BeautifulSoup([your markup])
to this:
BeautifulSoup([your markup], "lxml")
因此,如警告消息中所述,您只需将 soup = BeautifulSoup(html.read())
更改为 soup = BeautifulSoup(html.read(), 'lxml ')
,例如。
关于python - 属性错误 :'NoneType' 对象没有属性 'parent',我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43478806/