我有这个页面:
<html>
<head>
<title>Document Example</title>
</head>
<body>
<div id="container">
<div class="section">
<h1>Section 1</h1>
<li class="links">
<ul><a href="link.com/1"></a></ul>
<ul><a href="link.com/2"></a></ul>
<ul><a href="link.com/3"></a></ul>
</li>
</div>
<div class="section">
<h1>Section 2</h1>
<li class="links">
<ul><a href="link.com/4"></a></ul>
<ul><a href="link.com/5"></a></ul>
<ul><a href="link.com/6"></a></ul>
</li>
</div>
<div class="section">
<h1>Section 3</h1>
<li class="links">
<ul><a href="link.com/7"></a></ul>
<ul><a href="link.com/8"></a></ul>
<ul><a href="link.com/9"></a></ul>
</li>
</div>
</div>
</body>
</html>我想按部分分组链接:
driver.get("mypage.com")
sections = driver.find_elements_by_xpath("//div[@class='section']")
for section in sections:
section_name = section.find_element_by_xpath("//h1[@class='name']").get_attribute('innerHTML') #This fails
links = section.find_elements_by_xpath("//ul/a") #This find all links in page, not only links in section
问题是，我通过 xpath 在所有页面中找到了一个元素列表 (WebElement)，现在我想通过 xpath 找到元素部分内的所有特定元素，而不是在所有页面中。
怎么了？
编辑 1
这解决了问题(现在 xpath 以点 . 开头): driver.get("mypage.com")
sections = driver.find_elements_by_xpath("//div[@class='section']")
for section in sections:
section_name = section.find_element_by_xpath(".//h1[@class='name']").get_attribute('innerHTML') #This fails
links = section.find_elements_by_xpath(".//ul/a") #This find all links in page, not only links in section
最佳答案
可能有用
sections = driver.find_elements_by_xpath("//div[@class='section']")
for i, section in enumerate(sections):
section_name = section.text
links = section.find_elements_by_xpath("//div[@class='section'][%s]//a" % str(i+1))
关于python - 在 Webelement 中通过 xpath 查找 Selenium，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/50977255/