Python 从列表中返回不区分大小写的字符串，如果它包含不区分大小写的子字符串

Question

如果 list 包含不区分大小写的 substring，我如何从 string 返回不区分大小写的 string？返回的字符串应不区分大小写

我能够从列表中返回字符串，但我使用的是小写方法。我想在不修改的情况下将其恢复到原始状态

entriesList = ['CSS', 'Django', 'Git', 'HTML', 'Python']

substring = "g"

def substringSearch(substring, entriesList):
  return [string for string in (string.casefold() for string in entriesList) if substring in string] 


print(substringSearch(substring, entriesList))

结果:

['django', 'git']

我想得到什么:

['Django', 'Git']

Answer 1

您可以在理解测试中只使用 lower() 或 casefold()。

[string for string in entriesList if substring in string.casefold()]

您不需要为此制作新的生成器。这会给你:

entriesList = ['CSS', 'Django', 'Git', 'HTML', 'Python']

substring = "g"

def substringSearch(substring, entriesList):
      return [string for string in entriesList if substring in string.casefold()] 


print(substringSearch(substring, entriesList))

# ['Django', 'Git']