javascript - 需要一个标识符，却看到了 '0'

Question

如何修复这里的 jslint 错误？ https://jsfiddle.net/cfv2g1ho/

[JSLint was unable to finish] Expected an identifier and instead saw '0'.

function onYouTubeIframeAPIReady() {
    let playerVarsList = {
        0: {
            playerVars: {
                playlist: "0dgNc5S8cLI,mnfmQe8Mv1g,-Xgi_way56U,CHahce95B1g"
            }
        },
        1: {
            playerVars: {
                listType: "playlist",
                list: "PLYeOyMz9C9kYmnPHfw5-ItOxYBiMG4amq"
            }
        }
    }
    //to add the player to all the play buttons
    const totalP = document.querySelectorAll('[data-container="play1"]').length;

    //looping over all the play buttons and adding player to that
    for (let i = 0; i < totalP; i++) {
        players.add(".playSingle" + i, (playerVarsList[i] || {}));
    }
    players.add(".playInitial", {});

}

Answer 1

0 不是有效标识符，但是 "0" 是。但是您将对象作为数组处理 - 那么为什么不使用数组而不是对象呢？

    let playerVarsList = [
        {
            playerVars: {
                playlist: "0dgNc5S8cLI,mnfmQe8Mv1g,-Xgi_way56U,CHahce95B1g"
            }
        },
        {
            playerVars: {
                listType: "playlist",
                list: "PLYeOyMz9C9kYmnPHfw5-ItOxYBiMG4amq"
            }
        }
    ]

但是，如果您确实有某些理由绝对使用某个对象:

    let playerVarsList = {
        "0": {
            playerVars: {
                playlist: "0dgNc5S8cLI,mnfmQe8Mv1g,-Xgi_way56U,CHahce95B1g"
            }
        },
        "1": {
            playerVars: {
                listType: "playlist",
                list: "PLYeOyMz9C9kYmnPHfw5-ItOxYBiMG4amq"
            }
        }
    }

小心使用 strict mode混合数字和字符串时，例如如果启用严格模式，playerVarsList[i] 将不起作用。