在我的网络应用程序中我有这个模型:
InstagramAccount.php
UserPageFeed.php
每个 InstagramAccount 在 UserPageFeed 中有一条记录,并且每个 UserPageFeed 都属于 InstagramAccount 中的一条记录,那么这是一对一
关系,
问题:
my below code couldn't update existing row on table and create again
$userSelectedPage = InstagramAccount::whereUsername('my_page')->first();
$userPageFeeds = new UserPageFeed();
$userSelectedPage->account()->updateOrCreate([
'instagram_account_id' => $userPageFeeds->id, //exsiting row
'page_name' => 'test',
'feeds' => 'test',
'cache_time' => Carbon::now()->addHour(6),
]);
或此代码:
$userSelectedPage = InstagramAccount::whereUsername('content.world')->first();
$salam = $userSelectedPage->account()->updateOrCreate([
'instagram_account_id' => $userSelectedPage->id,
'page_name' => 'aaaaaaa',
'feeds' => 'ddd',
'cache_time' => Carbon::now()->addHour(6),
]);
user_page_feeds 表结构:
id ->Primary
instagram_account_id ->Index
feeds
page_name
cache_time
created_at
updated_at
有了这个索引:
"Keyname":user_page_feeds_instagram_account_id_foreign "Column":instagram_account_id
instagram_accounts 表结构:
id ->Primary
user_id ->Index
uid
fid
proxy
avatar
username
password
checkpoint
account_data
people_data
status
created_at
updated_at
InstagramAccount
型号:
class InstagramAccount extends Model
{
protected $guarded = ['id'];
protected $casts = [
'account_data' => 'array',
'people_data' => 'array'
];
public function user()
{
return $this->belongsTo(User::class);
}
public function account()
{
return $this->hasOne(UserPageFeed::class);
}
}
UserPageFeed
模型:
class UserPageFeed extends Model
{
public $incrementing = false;
protected $guarded = ['id'];
protected $casts = [
'feeds' => 'array'
];
public function account()
{
return $this->belongsTo(InstagramAccount::class,'instagram_account_id');
}
}
最佳答案
您必须使用带有两个单独参数的 updateOrCreate()
:
$userSelectedPage->account()->updateOrCreate(
['instagram_account_id' => $userPageFeeds->id],
[
'page_name' => 'test',
'feeds' => 'test',
'cache_time' => Carbon::now()->addHour(6),
]
);
第一个参数包含 Laravel 用来查找现有的属性
账号
.
第二个参数包含 Laravel 用于创建或更新 account
的属性。
关于php - Laravel 在 OneToOne 关系上更新或创建,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/50771638/