我已经在 php 中创建了网络服务。
现在我想在我的 iOS 应用程序中调用该 Web 服务。
我正在使用 JSON 解析来获取数据。
但它向我显示了一些错误。
我的代码:
SBJSON *json = [SBJSON new];
json.humanReadable = YES;
responseData = [[NSMutableData data] retain];
NSString *service = @"/getLastUpdated";
NSString *str;
str = @"LastUpdated";
NSString *requestString = [NSString stringWithFormat:@"{\"LastUpdated\":\"%@\"}",str];
// [[NSUserDefaults standardUserDefaults] setValue:nil forKey:@"WRONGANSWER"];
NSLog(@"request string:%@",requestString);
NSData *requestData = [NSData dataWithBytes: [requestString UTF8String] length: [requestString length]];
NSString *fileLoc = [[NSBundle mainBundle] pathForResource:@"URLName" ofType:@"plist"];
NSDictionary *fileContents = [[NSDictionary alloc] initWithContentsOfFile:fileLoc];
NSString *urlLoc = [fileContents objectForKey:@"URL"];
urlLoc = [urlLoc stringByAppendingString:service];
NSLog(@"URL : %@",urlLoc);
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:
[NSURL URLWithString: urlLoc]];
NSString *postLength = [NSString stringWithFormat:@"%d", [requestData length]];
[request setHTTPMethod: @"POST"];
[request setValue:postLength forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[request setHTTPBody: requestData];
NSError *respError = nil;
NSData *returnData = [NSURLConnection sendSynchronousRequest: request returningResponse: nil error: &respError ];
if (respError)
{
// NSString *msg = [NSString stringWithFormat:@"Connection failed! Error - %@ %@",
// [respError localizedDescription],
// [[respError userInfo] objectForKey:NSURLErrorFailingURLStringErrorKey]];
UIAlertView *alertView = [[UIAlertView alloc] initWithTitle:@"Sing It Say It"
message:@"check your network connection" delegate:self cancelButtonTitle:@"OK"
otherButtonTitles:nil];
[alertView show];
[alertView release];
}
else
{
NSString *responseString = [[NSString alloc] initWithData:returnData encoding: NSUTF8StringEncoding];
NSDictionary *results = [responseString JSONValue];
NSLog(@"results=%@",results);
NSString *extractUsers = [results objectForKey:@"d"];
// NSDictionary *finalResult = [extractUsers JSONValue];
NSLog(@"Final Result : %@",extractUsers);
[[NSUserDefaults standardUserDefaults] setValue:@"YES" forKey:@"NAVIGATION"];
[[NSUserDefaults standardUserDefaults] setValue:extractUsers forKey:@"NEWQUEID"];
}
错误:
2012-09-24 16:08:47.090 ACTEC_Webservice[3239:f803] -JSONValue failed. Error trace is: (
"Error Domain=org.brautaset.JSON.ErrorDomain Code=3 \"Unrecognised leading character\" UserInfo=0x6865bc0 {NSLocalizedDescription=Unrecognised leading character}"
)
2012-09-24 16:08:47.091 ACTEC_Webservice[3239:f803] results=(null)
2012-09-24 16:08:47.092 ACTEC_Webservice[3239:f803] Final Result : (null)
在响应字符串日志中显示这个值:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"/>
<title>404 - File or directory not found.</title>
<style type="text/css">
<!--
body{margin:0;font-size:.7em;font-family:Verdana, Arial, Helvetica, sans-serif;background:#EEEEEE;}
fieldset{padding:0 15px 10px 15px;}
h1{font-size:2.4em;margin:0;color:#FFF;}
h2{font-size:1.7em;margin:0;color:#CC0000;}
h3{font-size:1.2em;margin:10px 0 0 0;color:#000000;}
#header{width:96%;margin:0 0 0 0;padding:6px 2% 6px 2%;font-family:"trebuchet MS", Verdana, sans-serif;color:#FFF;
background-color:#555555;}
#content{margin:0 0 0 2%;position:relative;}
.content-container{background:#FFF;width:96%;margin-top:8px;padding:10px;position:relative;}
-->
</style>
</head>
<body>
<div id="header"><h1>Server Error</h1></div>
<div id="content">
<div class="content-container"><fieldset>
<h2>404 - File or directory not found.</h2>
<h3>The resource you are looking for might have been removed, had its name changed, or is temporarily unavailable.</h3>
</fieldset></div>
</div>
</body>
</html>
请帮帮我.. 谢谢。
最佳答案
行:
NSDictionary *results = [responseString JSONValue];
抛出异常，因为 responseString 不是 json。它是 HTML。您需要阅读 HTML 以发现错误:
<h2>404 - File or directory not found.</h2>
<h3>The resource you are looking for might have been removed, had its name changed, or is temporarily unavailable.</h3>
看来您的 URL 有误。
太糟糕了，尽管 JSONValue 失败得如此不优雅。如果确实如此，您将希望在生产代码中提供一些保护措施。在尝试解析之前以某种方式验证 json，或者实现异常处理程序。
关于php - mysql + json + iphone + 网络服务，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/12563364/