我有一个用 ipaddress.ip_network()
创建的 IPv4 和 IPv6 网络列表,我想排序(首先按家庭,然后按值(value))。最好的方法是什么?显然,天真的排序不起作用:
>>> from ipaddress import ip_network
>>> L = [ip_network(x) for x in ['ff00::/8', 'fd00::/8', '172.16.0.0/12', '10.0.0.0/8']]
>>> L.sort()
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "/usr/lib/python3.5/ipaddress.py", line 652, in __lt__
self, other))
TypeError: 10.0.0.0/8 and fd00::/8 are not of the same version
最佳答案
只需使用 key
function这将允许首先按类型比较值,例如:
>>> from ipaddress import ip_network, IPv6Network
>>> L = [ip_network(x) for x in ['ff00::/8', 'fd00::/8', '172.16.0.0/12', '10.0.0.0/8']]
>>> L.sort(key=lambda x: (isinstance(x, IPv6Network), x))
>>> L
[IPv4Network('10.0.0.0/8'), IPv4Network('172.16.0.0/12'), IPv6Network('fd00::/8'), IPv6Network('ff00::/8')]
关于python - 对 IPv4Network 和 IPv6Network 对象列表进行排序,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37485530/