我有以下脚本:
curl -s -S 'https://bittrex.com/Api/v2.0/pub/market/GetTicks?marketName=BTC-NBT&tickInterval=thirtyMin&_=1521347400000' | jq -r '.result|.[] |[.T,.O,.H,.L,.C,.V,.BV] | @tsv | tostring | gsub("\t";",") | "(\(.))"'
这是输出:
(2018-03-17T18:30:00,0.00012575,0.00012643,0.00012563,0.00012643,383839.45768188,48.465051)
(2018-03-17T19:00:00,0.00012643,0.00012726,0.00012642,0.00012722,207757.18765437,26.30099514)
(2018-03-17T19:30:00,0.00012726,0.00012779,0.00012698,0.00012779,97387.01596624,12.4229077)
(2018-03-17T20:00:00,0.0001276,0.0001278,0.00012705,0.0001275,96850.15260027,12.33316229)
我想用时间戳替换日期。
我可以在 shell 中用日期进行这种转换
date -d '2018-03-17T18:30:00' +%s%3N
1521325800000
我想要这样的结果:
(1521325800000,0.00012575,0.00012643,0.00012563,0.00012643,383839.45768188,48.465051)
(1521327600000,0.00012643,0.00012726,0.00012642,0.00012722,207757.18765437,26.30099514)
(1521329400000,0.00012726,0.00012779,0.00012698,0.00012779,97387.01596624,12.4229077)
(1521331200000,0.0001276,0.0001278,0.00012705,0.0001275,96850.15260027,12.33316229)
此数据存储在 MySQL 中。
是否可以在单个命令行中使用 jq 或其他命令(如 awk、sed、perl)执行日期转换？
最佳答案
这是一个假设“Z”(UTC+0)时区的全 jq 解决方案。
简而言之，只需将 .T 替换为:
((.T + "Z") | fromdate | tostring + "000")
要验证这一点，请考虑:
时间戳.jq
[splits("[(),]")]
| .[1] |= ((. + "Z")|fromdate|tostring + "000") # milliseconds
| .[1:length-1]
| "(" + join(",") + ")"
调用
jq -rR -f timestamp.jq input.txt
输出
(1521311400000,0.00012575,0.00012643,0.00012563,0.00012643,383839.45768188,48.465051)
(1521313200000,0.00012643,0.00012726,0.00012642,0.00012722,207757.18765437,26.30099514)
(1521315000000,0.00012726,0.00012779,0.00012698,0.00012779,97387.01596624,12.4229077)
(1521316800000,0.0001276,0.0001278,0.00012705,0.0001275,96850.15260027,12.33316229)
关于datetime - jq 解析日期到时间戳，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/49343797/