iphone - 如何使用 "OR"和 "AND"创建一个 compoundPredicate

Question

我获取了以下 3 个类别，但想添加一个“AND”谓词来缩小结果范围，其中“标记”处于打开状态。

NSMutableArray *questionNumberArray=[[NSMutableArray alloc] init];

// Fetch questions
NSManagedObjectContext *context = self.document.managedObjectContext;
NSFetchRequest *fetchRequest =
[[NSFetchRequest alloc] initWithEntityName:@"Questions"];

//building the predicate with selected category
NSMutableArray *parr = [NSMutableArray array];

if ([cat0str length]){
    [parr addObject:[NSPredicate predicateWithFormat:@"question.category CONTAINS[c] %@",cat0str]];
}
if ([cat1str length]){
    [parr addObject:[NSPredicate predicateWithFormat:@"question.category CONTAINS[c] %@",cat1str]];
}
if ([cat2str length]){
    [parr addObject:[NSPredicate predicateWithFormat:@"question.category CONTAINS[c] %@",cat2str]];
}

NSPredicate *compoundPredicate = [NSCompoundPredicate orPredicateWithSubpredicates:parr];

[fetchRequest setPredicate:compoundPredicate];

---

    NSPredicate *markPredicate =[NSPredicate predicateWithFormat:@"question.mark == 1"];
}

//我想做这样的事情:

NSPredicate *finalPredicate = [compoundPredicate && markPredicate];

[fetchRequest setPredicate:finalPredicate];

Answer 1

这是您要找的吗？

NSPredicate *finalPredicate = [NSCompoundPredicate andPredicateWithSubpredicates:
         [NSArray arrayWithObjects:compoundPredicate, markPredicate, nil]];

或者，对容器文字使用“现代 Objective-C”语法:

NSPredicate *finalPredicate = [NSCompoundPredicate andPredicateWithSubpredicates:
                                     @[compoundPredicate, markPredicate]];