kubernetes - 我如何获得 traefik.ingress.kubernetes.io/rule-type : PathPrefixStrip to work?

Question

我有以下 kubernetes list

apiVersion: extensions/v1beta1
kind: Ingress
metadata:
  annotations:
    kubernetes.io/ingress.class: traefik-external
    traefik.ingress.kubernetes.io/router.entrypoints: websecure, web
    traefik.ingress.kubernetes.io/rule-type: PathPrefixStrip
  name: ingressname
  namespace: thenamespace
spec:
  rules:
  - host: my.host
    http:
      paths:
      - backend:
          serviceName: theservice
          servicePort: 8080
        path: /api

有一个服务，theservice，监听/ 我希望 url my.host/api/something/anotherthing 匹配到/something/anotherthing 在 theservice 中。不过，这对我来说并没有发生，我得到了 404 返回。

任何想法可能是错误的？

Answer 1

在从 v1 到 v2 的过渡期间，Traefik 的许多内部部分和组件被重写和重组。因此，前端和后端等核心概念的组合已被 routers 的组合所取代。 , services , 和 middlewares .

使用 v2 转换传入请求的 URL 路径前缀配置为 middlewares对象，在带有 router rule PathPrefix 的路由步骤之后.

对于 v1，它是在入口级别定义的:

    apiVersion: networking.k8s.io/v1beta1
    kind: Ingress
    metadata:
      name: traefik
      annotations:
        kubernetes.io/ingress.class: traefik
        traefik.ingress.kubernetes.io/rule-type: PathPrefixStrip
    spec:
      rules:
      - host: company.org
        http:
          paths:
          - path: /admin
            backend:
              serviceName: admin-svc
              servicePort: admin

对于 v2，您还可以在入口路由旁边定义中间件对象:

apiVersion: traefik.containo.us/v1alpha1
kind: IngressRoute
metadata:
  name: http-redirect-ingressroute
  namespace: admin-web
spec:
  entryPoints:
    - web
  routes:
    - match: Host(`company.org`) && PathPrefix(`/admin`)
      kind: Rule
      services:
        - name: admin-svc
          port: admin
      middlewares:
        - name: admin-stripprefix
---
apiVersion: traefik.containo.us/v1alpha1
kind: Middleware
metadata:
  name: admin-stripprefix
spec:
  stripPrefix:
    prefixes:
      - /admin

更多信息可以在这里找到: Frontends and Backends Are Dead...
... Long Live Routers, Middlewares, and Services