python - 如何从屏幕上删除单个 pygame 绘图？

Question

当大圆圈接触小圆圈时，我希望它接触的小圆圈从屏幕上消失。但是，我无法弄清楚你是如何在 pygame 中删除单个绘图的。我该如何解决这个问题？ pygame 有内置这个功能吗？

from pygame import *
import random as rd
import math as m

init()
screen = display.set_mode((800, 600))

p_1_x = 200
p_1_y = 200
p_1_change_x = 0
p_1_change_y = 0

def p_1(x, y):
    player_1 = draw.circle(screen, (0, 0, 0), (x, y), 15)

def pick_up(x, y, xx, yy):
    distance = m.sqrt(m.pow(xx - x, 2) + m.pow(yy - y, 2))
    if distance < 19:
        # I think the code to delete should go here
        pass

dots = []
locations = []

for i in range(5):
    x = rd.randint(100, 700)
    y = rd.randint(100, 500)
    locations.append((x, y))

while True:
    screen.fill((255, 255, 255))
    for events in event.get():
        if events.type == QUIT:
            quit()
        if events.type == KEYDOWN:
            if events.key == K_RIGHT:
                p_1_change_x = 1
            if events.key == K_LEFT:
                p_1_change_x = -1
            if events.key == K_UP:
                p_1_change_y += 1
            if events.key == K_DOWN:
                p_1_change_y -= 1

        if events.type == KEYUP:
            if events.key == K_RIGHT or K_LEFT or K_UP or K_DOWN:
                p_1_change_x = 0
                p_1_change_y = 0

    p_1_x += p_1_change_x
    p_1_y -= p_1_change_y
    for i, locate in enumerate(locations):
        dot = draw.circle(screen, (0, 0, 0), locate, 5)
        dots.append(dot)
        for l in enumerate(locate):
            pick_up(p_1_x, p_1_y, locate[0], locate[1])

    p_1(p_1_x, p_1_y)
    display.update()

Answer 1

您的代码非常困惑且难以维护，首先我为 Balls & Dots 创建了 2 个类。 我通过 pygame.Rect.colliderect 检测碰撞，首先我制作 2 个矩形，然后像这样检查碰撞:

def pick_up(ball, dot):
    ball_rect = Rect( ball.x - ball.SIZE , ball.y - ball.SIZE , ball.SIZE*2, ball.SIZE*2)
    dot_rect = Rect( dot.x - dot.SIZE , dot.y - dot.SIZE , dot.SIZE*2, dot.SIZE*2)
    if ball_rect.colliderect(dot_rect): 
        return True
    return False

如果检测到碰撞，我会在 while 循环中将其从点数组中删除:

for dot in dots:
    if pick_up(ball, dot): # if dot in range ball
            dots.remove(dot)
    dot.draw()

这是完整的来源:

from pygame import *
import random as rd

SCREEN_WIDTH = 800
SCREEN_HEIGHT = 600
NUMBER_OF_DOTS = 5

class Ball():
    SIZE = 15
    def __init__(self, x, y):
        self.x = x
        self.y = y
        
    def draw(self):
        draw.circle(screen, (0, 0, 0), (self.x, self.y), Ball.SIZE)
    def move(self, vx, vy):
        self.x += vx
        self.y += vy

class Dot():
    SIZE = 5    
    def __init__(self, x, y):
        self.x = x
        self.y = y
        
    def draw(self):
        draw.circle(screen, (0, 0, 0), (self.x, self.y), Dot.SIZE)


def pick_up(ball, dot):
    ball_rect = Rect( ball.x - ball.SIZE , ball.y - ball.SIZE , ball.SIZE*2, ball.SIZE*2)
    dot_rect = Rect( dot.x - dot.SIZE , dot.y - dot.SIZE , dot.SIZE*2, dot.SIZE*2)
    if ball_rect.colliderect(dot_rect): 
        return True
    return False



init()
screen = display.set_mode((SCREEN_WIDTH, SCREEN_HEIGHT))

dots = []
ball = Ball(200,200)

# generate dots
for i in range(NUMBER_OF_DOTS):
    x = rd.randint(100, 700)
    y = rd.randint(100, 500)
    dots.append(Dot(x,y))

# the main game loop
while True:
    screen.fill((255, 255, 255))
    keys=key.get_pressed()

    for events in event.get():
        keys=key.get_pressed()
        if events.type == QUIT:
            quit()

    if keys[K_RIGHT]:
        ball.move(+1,0)
    if keys[K_LEFT]:
        ball.move(-1,0)
    if keys[K_UP]:
        ball.move(0,-1)
    if keys[K_DOWN]:
        ball.move(0,+1)

    for dot in dots:
        dot.draw()
        
        if pick_up(ball, dot):
                dots.remove(dot)

    ball.draw()
    display.update()
    time.delay(1) # Speed down

更新1:

PyGame 矩形碰撞 http://www.pygame.org/docs/ref/rect.html#pygame.Rect.colliderect

更新2:

我在github上做了一个repo，做了一些修改，
点是彩色的，新点的颜色是随机的，每当吃到一个点时球就会变大。

https://github.com/peymanmajidi/Ball-And-Dots-Game__Pygame