arrays - 在 golang 中 [:] syntax differ from the array assignment?

Question

我目前正在阅读 GoLang 教程并有以下疑问。

arr1:=[...]int{1,2,3}
arr2:=arr1
arr1[1]=99
fmt.Println(arr1)
fmt.Println(arr2)

它输出以下语句

[1 99 3]
[1 2 3]

here only array a is modified, which makes sense as an array is treated as values.

如果我尝试跟随事情变得困惑

a:=[...]int{1,2,3}
b:=a[:]
a[1]=88
fmt.Println(a)
fmt.Println(b)

这会导致打印

[1 88 3]
[1 88 3]

问题:这是否意味着说 b:=a 创建了数组的副本，说 b:=a[:] 将创建一个指向底层数组(本例中为“a”)？

Answer 1

Slicing does not copy the slice's data. It creates a new slice value that points to the original array. This makes slice operations as efficient as manipulating array indices. Therefore, modifying the elements (not the slice itself) of a re-slice modifies the elements of the original slice

https://blog.golang.org/slices-intro

检查上面的链接以了解 Slice 背后的内部结构