c# - 如何在 Spinner 中选择项目并将其用作字符串？

Question

只是想看看我是否能找出如何在微调器中选择项目并将其存储在字符串中，我已经看到了有关此问题的其他帖子，人们说将此行放入代码中: (在我在下面发布的代码的最后一行下方)

String Genders = Gender.getSelectedItem().toString();

我尝试了，但它在下面给了我一条红线 (getselecteditem()) - 说 spinner 不包含 getselecteditem() 的定义

这是我的代码:

  Spinner Gender;
  protected override void OnCreate(Bundle savedInstanceState)
    {
        base.OnCreate(savedInstanceState);
        SetContentView(Resource.Layout.Form);

        var Genders = new String[]
        {
            "Male", "Female"
        };
        BaseMale = 2000;
        Gender = FindViewById<Spinner>(Resource.Id.spinner1);
        Gender.Adapter = new ArrayAdapter<string>(this, Android.Resource.Layout.SimpleSpinnerDropDownItem, Genders);

非常感谢您的帮助! :)

Answer 1

您可能需要实现选择句柄 (ItemSelected)，如 https://developer.xamarin.com/guides/android/user_interface/spinner/ 中的示例所示:

protected override void OnCreate (Bundle bundle)
{
        base.OnCreate (bundle);

        // Set our view from the "Main" layout resource
        SetContentView (Resource.Layout.Main);

        Spinner spinner = FindViewById<Spinner> (Resource.Id.spinner);

        spinner.ItemSelected += new EventHandler<AdapterView.ItemSelectedEventArgs> (spinner_ItemSelected);
        var adapter = ArrayAdapter.CreateFromResource (
                this, Resource.Array.planets_array, Android.Resource.Layout.SimpleSpinnerItem);

        adapter.SetDropDownViewResource (Android.Resource.Layout.SimpleSpinnerDropDownItem);
        spinner.Adapter = adapter;
}

这里是句柄，所选项目的索引在此处显示为e.Position。

private void spinner_ItemSelected (object sender, AdapterView.ItemSelectedEventArgs e)
{
        Spinner spinner = (Spinner)sender;

        string toast = string.Format ("The planet is {0}", spinner.GetItemAtPosition (e.Position));
        Toast.MakeText (this, toast, ToastLength.Long).Show ();
}