ffmpeg for windows : error when concatenating videos

Question

我使用命令从名为 ca0.mp4...ca9.mp4 的分辨率为 1920x816 的视频文件中提取了一些剪辑

ffmpeg -i ./ca.mkv -ss 00:53:24 -t 00:01:30 ca0.mp4

然后我使用创建了一个黑色视频

ffmpeg -f lavfi -i color=black:s=1920x816:r=24000/1001 -f lavfi -i anullsrc -ar 48000 -ac 2 -t 00:00:02 empty.mp4

现在我想将剪辑与它们之间的黑色视频集中在一起。因此我创建了一个文件 list.txt:

file 'ca0.mp4'
file 'empty.mp4'
file 'ca1.mp4'
file 'empty.mp4'
file 'ca2.mp4'
file 'empty.mp4'
file 'ca3.mp4'
file 'empty.mp4'
file 'ca4.mp4'
file 'empty.mp4'
file 'ca5.mp4'
file 'empty.mp4'
file 'ca6.mp4'
file 'empty.mp4'
file 'ca7.mp4'
file 'empty.mp4'
file 'ca8.mp4'
file 'empty.mp4'
file 'ca9.mp4'

并尝试了命令

ffmpeg -f concat -i list.txt -c:v qtrle -c:a copy ca.mp4

但是，我得到以下输出:

ffmpeg version N-89940-gb1af0e23a3 Copyright (c) 2000-2018 the FFmpeg developers
  built with gcc 7.2.0 (GCC)
  configuration: --enable-gpl --enable-version3 --enable-sdl2 --enable-bzlib --enable-fontconfig --enable-gnutls --enable-iconv --enable-libass --enable-libbluray --enable-libfreetype --enable-libmp3lame --enable-libopencore-amrnb --enable-libopencore-amrwb --enable-libopenjpeg --enable-libopus --enable-libshine --enable-libsnappy --enable-libsoxr --enable-libtheora --enable-libtwolame --enable-libvpx --enable-libwavpack --enable-libwebp --enable-libx264 --enable-libx265 --enable-libxml2 --enable-libzimg --enable-lzma --enable-zlib --enable-gmp --enable-libvidstab --enable-libvorbis --enable-libvo-amrwbenc --enable-libmysofa --enable-libspeex --enable-libxvid --enable-libmfx --enable-amf --enable-cuda --enable-cuvid --enable-d3d11va --enable-nvenc --enable-dxva2 --enable-avisynth
  libavutil      56.  7.100 / 56.  7.100
  libavcodec     58.  9.100 / 58.  9.100
  libavformat    58.  7.100 / 58.  7.100
  libavdevice    58.  0.101 / 58.  0.101
  libavfilter     7. 11.101 /  7. 11.101
  libswscale      5.  0.101 /  5.  0.101
  libswresample   3.  0.101 /  3.  0.101
  libpostproc    55.  0.100 / 55.  0.100
[mov,mp4,m4a,3gp,3g2,mj2 @ 000001e2cd155900] Auto-inserting h264_mp4toannexb bitstream filter
Guessed Channel Layout for Input Stream #0.1 : 5.1
Input #0, concat, from 'list.txt':
  Duration: N/A, start: -0.021333, bitrate: 1894 kb/s
    Stream #0:0(eng): Video: h264 (High) (avc1 / 0x31637661), yuv420p, 1920x816 [SAR 1:1 DAR 40:17], 1500 kb/s, 23.98 fps, 23.98 tbr, 24k tbn, 47.95 tbc
    Metadata:
      handler_name    : VideoHandler
    Stream #0:1(ger): Audio: aac (LC) (mp4a / 0x6134706D), 48000 Hz, 5.1, fltp, 394 kb/s
    Metadata:
      handler_name    : SoundHandler
    Stream #0:2(eng): Data: bin_data (text / 0x74786574), 0 kb/s
    Metadata:
      handler_name    : SubtitleHandler
Stream mapping:
  Stream #0:0 -> #0:0 (h264 (native) -> qtrle (native))
  Stream #0:1 -> #0:1 (copy)
Press [q] to stop, [?] for help
[mp4 @ 000001e2cd213080] Could not find tag for codec qtrle in stream #0, codec not currently supported in container
Could not write header for output file #0 (incorrect codec parameters ?): Invalid argument
Error initializing output stream 0:0 --
Conversion failed!

谁能告诉我，我做错了什么？

Answer 1

由于所有文件都已从 .mkv 转换为 .mp4

您可能也只需要复制视频编解码器

ffmpeg -f concat -i list.txt -c:v copy -c:a copy ca.mp4

它也将加快进程