在最近的 post我在 中演示了如何使用数组参数。 Application.Index()
函数(而不是单个索引)
以任何方向重新排列当前列的顺序(切换列、省略/删除列)。
Application.Index(data, {vertical rows array}, {horizontal columns array})
这种方法不需要循环,并且允许仅通过在 OP 中列出新列位置来定义任何新列顺序,例如通过 Array(1, 4, 2)
换句话说Sub DeleteAndSwitch()
'[1]get data
Dim data: data = Sheet1.Range("A1:D4")
'[2]reorder columns via Array(1, 4, 2), i.e. get 1st column, 4th and 2nd column omitting the 3rd one
' (evaluation gets all existing rows as vertical 2-dim array)
data = Application.Index(data, Evaluate("row(1:" & UBound(data) & ")"), Array(1, 4, 2))
'[3]write to any target
Sheet2.Range("A1").Resize(UBound(data), UBound(data, 2)) = data
End Sub
相关评论问:"I can slice a 2D array, I can eliminate column, reorder columns, but I cannot ►insert a column(s) slice in such an array... In fact, I can do it using iteration, but did you find a similar way to insert such a vertical slice?"
有条不紊的提示
至少众所周知,给定的列(例如第 4 列)可以从数组(例如
data
)通过 Column4Data = Application.Index(data, 0, 4)
产生一个基于 1 的 2 维“垂直”数组。它是 不是 但是可以将垂直切片分配给另一个切片;以下代码将引发 1004 错误(应用程序定义或对象定义错误):
Application.Index(data, 0, 4) = Application.Index(data, 0, 1)
问题 Is there any possibility to insert a column(s) slice in an array (without iteration)?
确实存在将此类列数据排列在临时数组数组(“锯齿状数组”)中并从该基础构建 2-dim 数组的可能性。
为了不过度收费这篇文章,我将展示这种相当未知的方法作为►单独的答案期待任意 其他或更好的方法。
相关链接
Some pecularities of the
Application.Index()
function
最佳答案
使用 Application.Index()
的锯齿状阵列方法
为了完整起见,我展示了这种方法,以证明 Application.Index()
的进一步且广泛未知的可能性。功能。
通过首先将(转置)切片添加到临时“数组数组”中,可以在第二步中通过 创建一个二维数组。双零 使用以下语法的参数(参见 [2]b
部分):
data = Application.Transpose(Application.Index(data, 0, 0))
Sub InsertSlices()
'Auth: https://stackoverflow.com/users/6460297/t-m
'[0]define extra array (or slice AND transpose from other data source)
Dim Extra: Extra = Array(100, 200, 300, 400) ' example data
'[1]get data
Dim data: data = Tabelle7.Range("A1:D4")
'[2]a) rewrite data as 1-dim array of sliced column arrays
data = Array(Extra, Slice(data, 1), Slice(data, 4), Slice(data, 2))
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~
'[2]b) rebuild as 2-dim array
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~
data = Application.Transpose(Application.Index(data, 0, 0))
'[3]write to any target
Tabelle7.Range("F1").Resize(UBound(data), UBound(data, 2)) = data
End Sub
Function Slice(DataArr, ByVal colNo As Long) As Variant()
'Purpose: return entire column data as 2-dim array and
' transpose them here to get a "flat" 1-dim array of column data
With Application
Slice = .Transpose(.Index(DataArr, 0, colNo))
End With
End Function
警告:对于较大的数据集,分两步重复转换数据可能会很耗时。解决方法
因此,我更喜欢通过
Application.Index()
中的 ►array 参数引用的帖子中的基本方法。功能,但首先将一个(例如临时)列插入到物理数据范围,最终通过重新排列包含新添加的额外数据(最后一个位置)的列在任何新位置(例如,在顶部)。Sub DelSwitchAndInsert()
'Auth: https://stackoverflow.com/users/6460297/t-m
'[0]add other array data as last column to existing range
Sheet1.Range("E1:E4") = Application.Transpose(Array(1, 2, 3, 4))
'[1]get data
Dim data: data = Tabelle7.Range("A1:E4")
'[2]reorder via Array(1, 4, 2), i.e. get 1st column, 4th and 2nd column omitting the 3rd one
data = Application.Index(data, Evaluate("row(1:" & UBound(data) & ")"), Array(UBound(data, 2), 1, 4, 2))
'[3]write to any target
Sheet2.Range("A1").Resize(UBound(data), UBound(data, 2)) = data
End Sub
针对最近评论的解决方法附录 //编辑/2020-07-07在任何给定的“列”编号处插入垂直额外单列数据的解决方法逻辑的灵活示例如下:我不会假装这既不是最好的方法也不是最好的编码方式:
InsCol data, extra, 3 ' insertion e.g. as new 3rd "column"
Sub InsertExtraData()
'Purpose: insert a single-column array (2-dim, 1-based)
'[0]define extra array (or slice AND transpose from other data source)
Dim extra: extra = Application.Transpose(Array(100, 200, 300, 400)) ' example data
'[1]get data (or existing 2-dim array)
Dim data: data = Sheet1.Range("A1:D4")
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
'[2]insert extra as >>3rd<< column
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
InsCol data, extra, 3
'[3]write to any target
Sheet2.Range("A1").Resize(UBound(data), UBound(data, 2)) = data
End Sub
Sub InsCol(data, extra, Optional ByVal colNo As Long = 1)
With Sheets.Add
'[0]add data to temporary range
.Range("B1").Resize(UBound(data), UBound(data, 2)) = data
.Range("B1").Offset(0, UBound(data, 2)).Resize(UBound(extra) - LBound(extra) + 1, 1) = extra
'[1]get data
data = .Range("B1").Resize(UBound(data), UBound(data, 2) + 1)
'[2]reorder via Array(5, 1, 2, 3, 4)
data = Application.Index(data, Evaluate("row(1:" & UBound(data) & ")"), getColNums(data, colNo))
'[3]delete temporary sheet
Application.DisplayAlerts = False: .Delete
Application.DisplayAlerts = True
End With
End Sub
Function getColNums(main, Optional ByVal colNo As Long = 1) As Variant()
'c.f. : https://stackoverflow.com/questions/53727578/joining-two-arrays-in-vba/60082345#60082345
'Purp.: return ordinal element counters of combined 0-based 1-dim arrays
Dim i&, n&: n = UBound(main) + 1 ' +1 as one column, +1 from 0-based~>one-based
ReDim tmp(0 To n - 1) ' redim to augmented size (zero-based)
If colNo > n Then colNo = n
If colNo < 1 Then colNo = 1
For i = 0 To colNo - 1: tmp(i) = i + 1: Next i
tmp(colNo - 1) = n
For i = colNo To UBound(tmp): tmp(i) = i: Next i
getColNums = tmp ' return combined elem counters, e.g. Array(1,2, >>5<< ,3,4)
End Function
关于arrays - 将垂直切片插入数组,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/62722676/