python - 如何将列表值分配给excel文件中的列？

Question

我有一个列表值，并希望将其分配到 excel 文件中的列中。我要更改的值在表 6 中。
我糟糕的代码看起来像这样我能做的最好的事情是首先尝试将 AF6:AF22 更改为固定值 5，希望我可以将其更改为列表。
但是有没有一种简单的方法可以将 AF6:AF22 值更改为列表？
简单的 ws['AF6:AF22'] = l?

from openpyxl import Workbook
import pandas as pd
from openpyxl import load_workbook

l = list(range(5))

FilePath = 'excel_file.xlsx'
wb = load_workbook(FilePath)

ws = wb.worksheets

sheet_number = 6 

for sheet_number in ws.iter_cols('AF6:AF22'):
    for cell in sheet_number:
        cell.value = 5

Answer 1

选项 1
嗨 - 我在这里添加了一种更快的方法。这可能会更好，因为它避免了 for 循环并一次更新一个单元格。

from openpyxl import Workbook
import pandas as pd
from openpyxl import load_workbook

l = list(range(17))  #The list - You can replace l with whatever you need

with pd.ExcelWriter('excel_file.xlsx', mode='a', engine = 'openpyxl') as writer: 
    pd.DataFrame(l).to_excel(writer, sheet_name='Sheet6', startrow = 5, startcol= 31, index=False, header=None)

选项 2
您可以使用下面的代码来做您需要的事情。添加评论，让您了解我的逻辑......

from openpyxl import Workbook
import pandas as pd
from openpyxl import load_workbook

l = list(range(17))  #The list - You can replace l with whatever you need

FilePath = 'excel_file.xlsx'
wb = load_workbook(FilePath)

ws = wb.worksheets[5]  #Worksheet 5 is the 6th sheet as numbering starts from zero
for i in range(6,23):  # Column numbers 6 through 22
    ws.cell(row=i, column=32).value = l[i-6]  #Write to cell in AF = column 32
    
wb.save("excel_file.xlsx")