php - 尝试通过将用户名/密码发送到 PHP 脚本来验证 iOS 中的用户身份

Question

我试图通过从我的 iOS 应用程序向 php 脚本发送 POST 请求来验证用户身份。然后让 iOS 应用程序读取 NSHTTPURLResponse 以确定它是否成功。我的 iOS 代码如下所示，由于某种原因，它说我的 NSURLConnection 未使用。 int 代码总是返回值 200。

- (void)authenticateUser:(NSString *)aUsername
                password:(NSString *)aPassword
{
    NSString *post = [NSString stringWithFormat:@"username=%@&pw=%@", aUsername, aPassword];
    NSData *postData = [post dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES];
    NSString *postLength = [NSString stringWithFormat:@"%d", [post length]];

    NSURL *url = [NSURL URLWithString:@"http://XXX.com/query-db.php"];
    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0];
    [request setHTTPMethod:@"POST"];
    [request setValue:postLength forHTTPHeaderField:@"Content-Length"];
    [request setHTTPBody:postData];

    NSURLConnection *theConnection = [NSURLConnection connectionWithRequest:request delegate:self];
}

- (void) connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response{
    NSHTTPURLResponse* httpResponse = (NSHTTPURLResponse*)response;
    int code = [httpResponse statusCode];

    // Log the response
    NSLog(@"%d", code);
    if(code == 1){
        NSLog(@"received a 1");
        [self updateWorkTime];
        //[self close];
    } else {
        UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Unsuccessul Attempt" message:@"The username or password is invalid, please try again." delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil];
        [alert show];
        [alert release];
    }
}

此外，如果您想查看我的 php 脚本，我在虚拟变量中输入了该脚本并进行了测试，看看它是否正确查询了数据库并检查了...但以防万一您好奇。

<?php
    $sentUsername = $_POST['username'];
    $sentPW = $_POST['pw'];

    mysql_connect("xxx", "xxx", "xxx") or die(mysql_error());   
    mysql_select_db("xxx") or die(mysql_error());

    $result = mysql_query("SELECT * FROM Table") or die(mysql_error());  

    $authenticate = 0;

    while($authenticate == 0) {
        $row = mysql_fetch_array($result);
        $selectedUsername = $row['username'];
        $selectedPW = $row['pw'];
        $pwComp = strcmp($sentPW, $selectedPW);
        $userComp = strcmp($selectedUsername, $sentUsername);

        if(!$row) break;
        if($selectedPW == $sentPW && $selectedUsername == $sentUsername) {
            $authenticate = 1;
        }
    }
    echo $authenticate;
?>

我尝试设置 PHP header ，但我不确定如何执行此操作。我感谢这个社区给我的所有帮助，这真的非常宝贵。谢谢!

Answer 1

您返回的“200”代码是 HTTP 状态代码，表示请求成功。

如果您想要从 PHP 脚本发回“1”或“0”值，则应该在 didReceiveData: 委托(delegate)方法中查找它，而不是 didReceiveResponse: .

- (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)theData
{
    NSLog(@"authenticate value => %@",[[NSString alloc] initWithData:theData encoding:NSUTF8StringEncoding]);
}