iPhone 谷歌地理编码请求失败

Question

我想使用谷歌地理编码来查找带有名称的地点纬度经度列表，我没有在iPhone中使用此功能的经验，但在Android中只需调用网址即可。但是当我在 iPhone 中尝试相同的操作时，它给我错误“请求被拒绝”。指导我如何将其集成到 iPhone 中，或者我应该使用像 BSForwardGeocoder 这样的库，我正在这样做

NSString *url = [NSString stringWithFormat:@"http://maps.googleapis.com/maps/api/geocode/json?address=%@&sensor=true", locationString];
url = [url stringByReplacingOccurrencesOfString:@" " withString:@"%20"];

NSURL *wurl = [NSURL URLWithString:url];
NSDictionary *dict =  [Json objectWithUrl:wurl];
NSLog(@"%@", dict);

它打印为

{
results =     (
);
status = "REQUEST_DENIED";
}

Answer 1

检查这个

NSString *locationString = @"1600 Amphitheatre Parkway, Mountain View, CA";
NSString *url = [NSString stringWithFormat:@"http://maps.googleapis.com/maps/api/geocode/json?address=%@&sensor=true", locationString];
url = [url stringByReplacingOccurrencesOfString:@" " withString:@"%20"];

NSURL *wurl = [NSURL URLWithString:url];
NSData *data = [NSData dataWithContentsOfURL: wurl];

// Fail to get data from server
if (nil == data) {

    NSLog(@"Error: Fail to get data");
}
else{
    // Parse the json data
    NSError *error;
    NSDictionary *json = [NSJSONSerialization
                          JSONObjectWithData:data
                          options:kNilOptions
                          error:&error];

    // Check status of result
    NSString *resultStatus = [json valueForKey:@"status"];

    // If responce is valid
    if ( (nil == error) && [resultStatus isEqualToString:@"OK"] ) {

        NSLog(@"%@", json);
    }
}

引用:The Google Geocoding API